V 1 = 500 mph,
v 2 = 50 mph
The resultant velocity:
v r² = v 1 ² + v 2 ²
v r ² = 500² + 50² = 250,000 + 2,500 = 252,500
v r = √252,500 = 502.49378 ≈ 502.49 mph
Answer: the magnitude of the resultant velocity is 502.49 mph.
Answer:
Step-by-step explanation:
In ΔACB and ΔCAD,
AD║BC and AC is a transverse [Given]
∠BCA ≅ ∠DAC [Alternate interior angles]
AC ≅ AC [Reflexive property]
BC ≅ AD [Given]
ΔACB ≅ ΔCAD [By SAS property of congruence]
From the second figure,
In ΔJHG and ΔLKH,
JH ≅ LK [Given]
JG ≅ LH [Given]
GH ≅ HK [Given]
Therefore, ΔJHG ≅ ΔLKH [By SSS property of congruence]
Answer:
what's the problem? the I should answer?
Its the last answer (-1+radical 3)/2
You multiply with the opposite so you multiply 1/1+radical 3 with 1- radical 3/1-radical 3 I hope its helpful:)
