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Contact [7]
2 years ago
10

A nuclear power plant has two independent safety systems. The probability the first will not operate properly in an emergency P

(A) is 0.01, and the probability the second will not operate P (B) in an emergency is 0.03. What is the probability that in an emergency both of the safety systems will not operate?

Mathematics
1 answer:
Hatshy [7]2 years ago
3 0

Step-by-step explanation:

they are independent systems, so in case of an emergency both systems will activate.

this is like rolling 2 dice and asking for the probability that both will show 1.

the probability that both will fail is the product of the individual probabilities for failure :

0.01 × 0.03 = 0.0003

so, the third answer option is correct.

FYI - the probability for 2 dice to both roll 1 is

1/6 × 1/6 = 1/36

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how many pounds of candy worth $12 per pound should be mixed with candy costing $19 per pound to produce a 70 pound mixture that
sweet-ann [11.9K]

Answer:

40 pounds

Step-by-step explanation:

Given: Cost of a candy (c_1)= \$ 12 per pound

           Cost of candy (c_2) = \$ 19\ per\ pound

           Total amount of mixture of be produced = 70\ pound

           Selling price of mixture = \$ 15 \ per\ pound

Let´s x be the amount of c_1 to be mixed in the mixture.

∴ Cost of c_1 in the mixture = 12x

Next, Cost of c_2 in the mixture = (70 - x)\times 19

And we know the cost of final mixture = 70 \times 15 = 1050

Now, putting all the value in the equation

⇒ 12x + 19 \times (70 - x) = 1050

⇒ 1330 - 7x = 1050

⇒ -7x = -280

∴ x = 40\ pound

∴ 40 pounds of candy worth $12 per pound to be mixed in the mixture.

6 0
3 years ago
WILL MARK BRAINLIEST '<br> IF YOU DONT KNOW DONT ANSWER
Soloha48 [4]

Answer: A) Alternate Exterior

Step-by-step explanation:

Let's find out the defenition of alternate exterior; "If a pair of parallel lines are cut by a transversal line, then the alternate exterior angles are congruent".

I hope this helps!

8 0
3 years ago
Find MN <br> Segment addition postulate
lisabon 2012 [21]

Answer:

<h2>MN= 6</h2>

Step-by-step explanation:

<h3>Let MP= 32 and NP = 26</h3><h3 /><h3>32 - 26 = 6</h3><h3 />

\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}

7 0
3 years ago
Do all rational equations have a single solution? why? is there a time when a rational equation doesn't have a solution?
abruzzese [7]
<span>Answer: All rational equations don’t necessary have a single solution however they do have solutions that can’t fulfill the answer. Any solution where the denominator is equal to zero results in an undefined equation.</span>
8 0
3 years ago
The numerical value of sin²5° + sin²10° + sin²15° +... sin²85° + sin²90° is equal a) 17/2 b) 19/2 c) 15/2 d) 13/2​
Vikki [24]

Answer: b)~\Large\boxed{\frac{19}{2} }

Step-by-step explanation:

<h3>Given expression</h3>

sin²5° + sin²10° + sin²15° +... sin²85° + sin²90°

<h3>Concept:</h3>

sin²x + cos²x = 1

sin(x) = cos (90 - x)

<u />

<u>There are in total these terms:</u>

5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70, 75, 80, 85, 90

<u>In total, there are 18 terms, and the first one matches with the second to the last one:</u>

5 -- 85

10 -- 80

.

.

.

40 -- 50

<u />

<u>There are 2 terms left over:</u>

sin²45 and sin²90

<h3>Convert the first half of the sine terms (sin²5 - sin²40) to the cosine terms</h3>

sin²5 = cos² (90 - 5) = cos²85

sin²10 = cos² (90 - 10) = cos²80

.

.

.

sin²40 = cos² (90 - 40) = cos²50

<h3>Simplify the 16 grouped terms </h3>

<em>i.e. sin²85 and cos²85</em>

Using the concept of sin²x + cos²x = 1

sin²85 + cos²85 = 1

sin²80 + cos²80 = 1

.

.

.

sin²50 + cos²50 = 1

Total = (16/2) × 1 = 8 × 1 = 8

<h3>Evaluate the 2 terms that are left over</h3>

sin²45 = (sin45) (sin45) = (√2 / 2) (√2 / 2) = 1/2

sin²90 = (sin90) (sin 90) = (1) (1) = 1

<h3>Add all the terms together</h3>

8+\dfrac{1}{2} +1=\Large\boxed{\frac{19}{2} }

Hope this helps!! :)

Please let me know if you have any questions

8 0
1 year ago
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