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1 year ago

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A nuclear power plant has two independent safety systems. The probability the first will not operate properly in an emergency P

(A) is 0.01, and the probability the second will not operate P (B) in an emergency is 0.03. What is the probability that in an emergency both of the safety systems will not operate?

1 answer:

Hatshy [7]1 year ago

3 0

Step-by-step explanation:

they are independent systems, so in case of an emergency both systems will activate.

this is like rolling 2 dice and asking for the probability that both will show 1.

the probability that both will fail is the product of the individual probabilities for failure :

0.01 × 0.03 = 0.0003

so, the third answer option is correct.

FYI - the probability for 2 dice to both roll 1 is

1/6 × 1/6 = 1/36

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Here are six number cards.

patriot [66]

Answer:

-7 3=-4

-5 1=-4

-3 -1=-4

-7 and 3 make -4. -5 and 1 make -4. -3 and -1 make -4.

6 0

3 years ago

Read 2 more answers

Consider the following information related to a set of quantitative sample data:

svlad2 [7]

Answer:

(a) There are outliers

(b) $x$ and $x >62$

Step-by-step explanation:

Given

$\sigma = 14.92$

$\bar x = 22.0$

$q_0 = -24$

$q_1 = 14.5$

$q_2 = 24.5$

$q_3 = 33.5$

$q_4 = 64$

Solving (a): Check for outliers

This is calculated using:

$Lower = Q_1 - (1.5 * IQR)$ --- lower bound of outlier

$Upper = Q_3 +(1.5 * IQR)$ --- upper bound of outlier

Where

$IQR = Q_3 - Q_1$

So, we have:

$IQR = 33.5 - 14.5$

$IQR = 19$

The lower bound of outlier becomes

$Lower = Q_1 - (1.5 * IQR)$

$Lower = 14.5 - (1.5 * 19)$

$Lower = 14.5 - 28.5$

$Lower = -14$

The upper bound of outlier becomes

$Upper = Q_3 +(1.5 * IQR)$

$Upper = 33.5 + 1.5 * 19$

$Upper = 33.5 + 28.5$

$Upper = 62$

So, we have:

$-14 \le x \le 62$ --- the range without outlier

Given that:

$q_0 = -24$ --- This represents the lowest data

$q_4 = 64$ --- This represents the highest data

-24 and 64 are out of range of $-14 \le x \le 62$ .

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

$x$ and $x >62$

4 0

2 years ago

#11-16 please 15 points

Serjik [45]

11. Similar 1/2
12. Similar 2
13. no
14. no
15. No, they are not congruent because rectangles do not have equal sides, so the length of one triangle could be longer than the other and the width ozone can be shorter than the other.
16. Yes

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3 years ago

An object is launched directly in the air at a speed of 48 feet per second from a platform located 12 feet above the ground. The

anastassius [24]

9514 1404 393

Answer:

48 ft

Step-by-step explanation:

For the quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a). For the given quadratic, which defines a parabola opening downward, the axis of symmetry defines the time at which the maximum height is reached.

t = -48/(2(-16)) = 1.5

Then the maximum height is ...

f(1.5) = (-16·1.5 +48)1.5 +12 = (24·1.5) +12

f(1.5) = 48

The maximum height the object will reach is 48 feet.

6 0

3 years ago

A school plays a series of 6 soccer matches. For each match there are 3 possibilities: a win, a draw or a loss. How

Sphinxa [80]

Answer:

There are 729 possible results are there for the series

Step-by-step explanation:

If we have n trials, each with m possible outcomes, the total number of possible outcomes is:

$T = m^{n}$

In this question:

6 games(trials), so $n = 6$ .

Each with three possible outcomes, so $m = 3$

Then:

$T = 3^{6} = 729$

There are 729 possible results are there for the series

7 0

3 years ago