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IRINA_888 [86]
3 years ago
13

Yeah just help me thank you....

Mathematics
2 answers:
schepotkina [342]3 years ago
7 0

Answer:

47

Step-by-step explanation:

mash [69]3 years ago
6 0

Answer:

47

Step-by-step explanation:

Plug the numbers in and solve

5 ^ 2 + 2 ( 5 + 6 )

25 + 22

47

also plz mark me brainiest

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3 years ago
Which of the following is an extraneous solution of startroot 4 x 41 endroot = x 5? x = –8 x = –2 x = 2 x = 8
Gnom [1K]

The extraneous solution of startroot 4 x 41 endroot = x 5 will be A. -8.

<h3>What is an extraneous solution?</h3>

It should be noted that an extraneous solution simply means a root of a transformed equation which isn't part of the original equation.

✓4x + 41 = x + 5

Square both sides

4x + 41 = x² + 10x + 25

x² + 6x - 16

x(x + 8) - 2(x + 8) = 0

x + 8 = 0

x= 0 + 8 = 8

Learn more about extraneous solution on:

brainly.com/question/295656

#SPJ4

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