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seropon [69]
3 years ago
7

N the drawing, six out of every 10 tickets are winning tickets. Of the winning tickets, one out of every three awards is a large

r prize.
What is the probability that a ticket that is randomly chosen will award a larger prize?

Two-fifteenths
One-fifth
Five-ninths
Five-sixths
Mathematics
2 answers:
skad [1K]3 years ago
6 0

Answer:

1/5

Step-by-step explanation:

MaRussiya [10]3 years ago
5 0

the answer would be one-fifth :)

hope this helped

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VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.
mario62 [17]

Answer:

Coordinates switch, and the new y-coordinate changes sign

Explanation:

We have point A with the coordinates (-1,2), when we rotate it c90º it becomes (2,1).

What happened? The coordinates switched and the x-coordinate of A (-1) became the y-coordinate of A' (1) and it changed its sign.

7 0
3 years ago
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Are the dotted lines in the shape parallel, perpendicular or intersecting?
slava [35]

Answer:

<em>Parallel</em>

Step-by-step explanation:

The dotted lines are parallel because they have the same <u>gradient</u> to each other, this means the two dotted lines will <u>never</u> touch each other.

Have a great day <3

8 0
3 years ago
Referring to the figure, what is the slope of the<br> line?
sweet [91]

Answer:

sorry i dont know, i just rlly need points

Step-by-step explanation:

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3 years ago
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Question content area top
BigorU [14]

The volume of the slice is 40 in³. The volume of the remaining cake would be 197.014 in³.

<h3>What is a regular hexagon?</h3>

A regular hexagon can be defined as a closed shape consisting of six equal sides and six equal angles.

Here we have two regular hexagons

one top small hexagon cake with a side of length = 3 in, height = 3 in

One big hexagon cake, side of length = 4 in, Height = 4 in

A slice cut such that it removes a side segment is equivalent to an equilateral triangle with a side

length = length of hexagon side

The length of the side of the removed equilateral triangle side

Top small cake slice triangle side = 3 in.

Area of surface of small slice = 1/2 x b x h = 1/2 x 3 x 3 x sin 60

                                                = 9√3/ 4

The volume of a small slice  

=  Area of surface small slice × Height of small cake

= 9√3/ 4  x 3

= 11. 69

Big cake slice triangle side = 4 in.

Area of the surface of big slice = 1/2 x 4 x 4 x sin 60

                                                    = 4√3

The volume of big slice =  Area of the surface of big slice × Height of big slice

= 16√3

= 28

The total volume of slice = Volume of small slice + Volume of big slice

Total volume of slice = 12 in³ +28 in³ = 40 in³

For the small cake,

the remaining volume = 5 x 11.69 = 58.45

For the big cake

the remaining volume = 5 x 27.71 = 138.56

Total volume remaining cake

= 58.45 in³ + 138.56 in³ = 197.014 in³

a = Length of side

h = Height of hexagon

The volume of each slice is,

= a^2 x h x √3/4

For the small cake, we have

a = 3 in.

h = 3 in.

The volume of small slice = a^2 x h x √3/4

                                   = 9 x 3 x √3/4

                                   = 27√3/4

For the big cake, we have

a = 4 in.

h = 4 in.

Volume of big slice =  a^2 x h x √3/4

                                = 16 √3

The total volume of slice = Volume of small slice + Volume of a big slice

Total volume of slice = 27√3/4 + 16 √3

The total volume of the slice = 39404 in³.

Learn more about hexagon;

brainly.com/question/16025389

#SPJ1

3 0
2 years ago
Consider the initial value problem y′′+36y=2cos(6t),y(0)=0,y′(0)=0. y″+36y=2cos⁡(6t),y(0)=0,y′(0)=0. Take the Laplace transform
Bingel [31]

Recall the Laplace transform of a second-order derivative,

L(y''(t)) = s^2Y(s)-sy(0)-y'(0)

and the transform of cosine,

L(\cos(at))=\dfrac s{a^2+s^2}

Here, both y(0)=y'(0)=0, so taking the transform of both sides of

y''(t)+36y(t)=2\cos(6t)

gives

s^2Y(s)+36Y(s)=\dfrac{2s}{36+s^2}

\implies Y(s)=\dfrac{2s}{(s^2+36)^2}

4 0
3 years ago
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