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Rasek [7]
3 years ago
8

The home states of a certain group of people are distributed as follows: 52 percent are from MISSOURI, 28 percent are from KANSA

S, and 20 percent are from IOWA. (No one in the group had a home state other than one of these three.) (Note: Your answer to the question below should be rounded to three decimal places.) Suppose we randomly select a person from this group. What is the expected value of the number of letters in the selected person's home state
Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

The expected value of the number of letters in the selected person's home state is 6.64.

Step-by-step explanation:

What is the expected value of the number of letters in the selected person's home state

52% have 8 letters(Missouri).

28% have 6 letters(Kansas)

20% have 4 letters(Iowa).

So

E = 0.52*8 + 0.28*6 + 0.2*4 = 6.64

The expected value of the number of letters in the selected person's home state is 6.64.

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Answer:

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Step-by-step explanation:

3f + 9 < 21

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JulijaS [17]

Answer:

\frac{dT}{dt}=3.78^{\circ}K/min

Step-by-step explanation:

We have to calculate the time derivative of T=PV/nR with P and V variable and n and R constants. This is:

\frac{dT}{dt} =\frac{d\frac{PV}{nR}}{dt}=\frac{1}{nR}\frac{d(PV)}{dt}

What we have to do is the derivative of a product:

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Substituting, we have:

\frac{dT}{dt} =\frac{P\frac{dV}{dt}+V\frac{dP}{dt}}{nR}

where all these values are given since the time derivatives of P and V are their variation rate, using minutes.

We then substitute everything, noticing that already everything is in the same system of units so they cancel out:

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3 years ago
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Alenkasestr [34]

Answer:

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Step-by-step explanation:

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answer
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My guess would be distributive. i maybe be wrong so don't get mad if I'm wrong.

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