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jeyben [28]
3 years ago
8

You toss a coin three times. What is the probability of getting three heads?

Mathematics
2 answers:
RSB [31]3 years ago
5 0

Answer:1/6

Step-by-step explanation: So you toss it 3 times(1/3) and you have 50% chance(1/2) of choosing heads or tails... so,

1/3 x 1/2 = 1/6

Delvig [45]3 years ago
5 0

Answer:

I think you have a 2 or 6 percent chance. I haven't done this in a while. Check for me, k?

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I could use your help here​
Norma-Jean [14]

Answer:

-1

Step-by-step explanation:

i= -1^(1/2)

= -1^(1/2 x 34)

= -1^(17)

= -1

3 0
3 years ago
Evaluate the given expression if x=25, y=10, w=45, and z=10 (x-y)^2+10wz
katen-ka-za [31]

Answer:

4725

Step-by-step explanation:

25-10=15

15^2=225

10*45*10=4500

225+4500=4725

4 0
3 years ago
HURRY!! WHOEVER ANSWERS FIRST WILL BE THE BRAINLIEST!!
beks73 [17]
These answers are all the same equation :/ they are all right, they all go right through the point :/
4 0
3 years ago
Round 12.03994 to 3 decimal place
Misha Larkins [42]
12.03994\to\boxed{12.04}
8 0
3 years ago
After an extensive advertising campaign, the manager of a company expects the proportion of potential customers that recognize a
lina2011 [118]

Answer:

Step-by-step explanation:

Hello!

The study variable is:

X: number of customers that recognize a new product out of 120.

There are two possible recordable outcomes for this variable, the customer can either "recognize the new product" or " don't recognize the new product". The number of trials is fixed, assuming that each customer is independent of the others and the probability of success is the same for all customers, p= 0.6, then we can say this variable has a binomial distribution.

The sample proportion obtained is:

p'= 54/120= 0.45

Considering that the sample size is large enough (n≥30) you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal: p' ≈ N(p;\sqrt{\frac{p(1-p)}{n} })

The other conditions for this approximation are also met: (n*p)≥5 and (n*q)≥5

The probability of getting the calculated sample proportion, or lower is:

P(X≤0.45)= P(Z≤\frac{0.45-0.6}{\sqrt{\frac{0.6*0.4}{120} } })= P(Z≤-3.35)= 0.000

This type of problem is for the sample proportion.

I hope this helps!

5 0
3 years ago
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