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3 years ago

You toss a coin three times. What is the probability of getting three heads?

Mathematics

2 answers:

RSB [31]3 years ago

5 0

Answer:1/6

Step-by-step explanation: So you toss it 3 times(1/3) and you have 50% chance(1/2) of choosing heads or tails... so,

1/3 x 1/2 = 1/6

Delvig [45]3 years ago

5 0

Answer:

I think you have a 2 or 6 percent chance. I haven't done this in a while. Check for me, k?

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Given the two points write the equation for the line in slope intercept

andrezito [222]

Answer:

y = -1/2x + 2

Step-by-step explanation:

I think it is

use slope formula to find your slope.

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boom roasted.

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3 years ago

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Likurg_2 [28]

its the third answer

Step-by-step explanation:

and its only 5 points not 30

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3 years ago

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4 years ago

A cable car starts off with n riders. The times between successive stops of the car are independent exponential random variables

nikitadnepr [17]

Answer:

The distribution is $\frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}$

Solution:

As per the question:

Total no. of riders = n

Now, suppose the $T_{i}$ is the time between the departure of the rider i - 1 and i from the cable car.

where

$T_{i}$ = independent exponential random variable whose rate is $\lambda$

The general form is given by:

$T_{i} = \lambda e^{- lambda}$

(a) Now, the time distribution of the last rider is given as the sum total of the time of each rider:

$S_{n} = T_{1} + T_{2} + ........ + T_{n}$

$S_{n} = \sum_{i}^{n} T_{n}$

Now, the sum of the exponential random variable with $\lambda$ with rate $\lambda$ is given by:

$S_{n} = f(t:n, \lamda) = \frac{\lambda^{n}e^{- \lambda t}t^{n - 1}}{(n - 1)!}$

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3 years ago