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Bond [772]
3 years ago
6

You buy 4 pieces of chicken for $8.80. Write an equation that can be used to express the relationship between the total price t

and the pieces of chicken c you buy.
Mathematics
2 answers:
Phoenix [80]3 years ago
5 0

Answer:

t=$2.20c

Step-by-step explanation:

4 pieces of chicken for $8.80

Cost of 4 pieces of chicken=$8.80

$8.80/4=$2.20 for each chicken

t=$2.20c

babymother [125]3 years ago
5 0

Answer:

t=c*8.80/4

Step-by-step explanation:

one piece is 8.80/4

so t= c *8.80/4

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7. Nick’s youth group has 20 regular students that attend weekly get togethers. They saved up enough money for each person to go
Anna11 [10]

Answer:

If each youth saves $10 daily, their weekly savings would be $1400. So they donated $1400 to the church.

Step-by-step explanation:

Let the daily pay plan for each youth be $y

Daily pay plan for 20 youth = $20y

Weekly pay plan = 7×20y = $140y

Assuming each youth saves $10 daily

Daily savings for 20 youth = 20×$10= $200

Weekly savings for 20 youth = 7×$200= $1400

If they used the early pay plan ($140y) to go swimming, they saved $1400 which they donated to the church.

6 0
3 years ago
Graph the line passing through (−2,5) whose slope is m=1/5
Nonamiya [84]

Hello there! :)

Given:

x-coordinate of point = -2

y-coordinate of point = 5

Slope, or "m" = 1/5

Substitute in these values into slope-intercept formula (y = mx+b)

5 = 1/5(-2) + b

5 = -2/5 + b

25/5 = -2/5 + b

27/5 = b

Rewrite the equation:

y = 1/5x + 27/5

Graph the equation using a graphing utility:

4 0
3 years ago
Read 2 more answers
I got 77 for my total answer. I correct? if not can some help​
mote1985 [20]
Yes you got it correct.
8 0
3 years ago
Read 2 more answers
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
I NEED HELP FAST!!!! 15PTS
Vadim26 [7]
3.option a (-8,2)

4.option b (5,4)
7 0
3 years ago
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