Answer:
Rate at which spring is oscillating 2.9631
Step-by-step explanation:
The governing equation for the position of the spring = 3 sin t
the change in position of the spring with respect to time is =
given time t = 9 seconds,
To find the rate at which the spring is oscillating at the time, we insert the time 9 seconds into the the slot for t
rate at which it is oscillating = 2.9631
Since there are 16 oz in 1lb, 1/16 of a pound is one ounce.
Hope I helped!
Best of Luck :)
Answer:
(f - g)(3) = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 4x - 2
g(x) = x + 1
<u>Step 2: Find</u>
<em>Find (f - g)(x)</em>
- Substitute: (f - g)(x) = 4x - 2 - (x + 1)
- Distribute -1: (f - g)(x) = 4x - 2 - x - 1
- Combine like terms: (f - g)(x) = 3x - 3
<em>Find (f - g)(3)</em>
- Substitute: (f - g)(3) = 3(3) - 3
- Multiply: (f - g)(3) = 9 - 3
- Subtract: (f - g)(3) = 6
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Step-by-step explanation:
