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3 years ago

Which equation descibes the pattern shown in the table?

Mathematics

1 answer:

Verdich [7]3 years ago

5 0

The answer is D. If you put all of the values into the equation the only one that works for all of them is D

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Factor each completely x^3^a -27y^6^B<br><br>Pls need help<br>From: Brainly.ph (Philippine's)

sp2606 [1]

Answer:

$= ( {x}^{a} - {3y}^{2b} ) \times ( {x}^{2a} + {3x}^{a} {y}^{2b} + {9y}^{4b} )$

Step-by-step explanation:

${x}^{3a} - 27 {y}^{6b}$

$( {x}^{a} {)}^{3} - {3}^{3} \times ( {y}^{2b} {)}^{3}$

$( {x}^{a} {)}^{3} - (3 {y}^{2b} {)}^{3}$

$( {x}^{a} - {3y}^{2b} ) \times (( {x}^{a} {)}^{2} + {x}^{a} \times {3y}^{2b} + ( {3y}^{2b} {)}^{2} )$

$\boxed{\green{= ( {x}^{a} - {3y}^{2b} ) \times ( {x}^{2a} + {3x}^{a} {y}^{2b} + {9y}^{4b})}}$

3 0

3 years ago

A rectangular parking lot has an area of 315 square yards. The width of the parking lot is 5 yards longer than the length of the

Blababa [14]

Answer:

Dimension of parking lot is approximately 15.425 × 20.425 yards.

Step-by-step explanation:

Given:

Area of the parking lot = $315 \ yd^2$

Let the length of the parking lot be $'l'$

Also Given:

The width of the parking lot is 5 yards longer than the length of the parking lot.

so we can say that;

width of the parking lot, $w=5+l$

We need to find the dimension of parking lot.

Solution:

Now we can say that;

Area of rectangle is equal to length times width.

framing in equation form we get;

$lw=315$

Now substituting the value of w in above equation we get;

$l(l+5)=315\\\\l^2+5l=315\\\\l^2+5l-315=0$

Now we will find the roots using quadratic equation.

$ax^2+bx+c =0$

a = 1

b=5

c=-315

Formula for quadratic equation is;

$l =\frac{-b\±\sqrt{b^2-4ac}}{2a}$

First we will find;

$\sqrt{b^2-4ac} = \sqrt{5^2-4\times1\times-315} =\sqrt{25+1260}=\sqrt{1285} \approx35.85$

Now we will substitute the value we get;

$l =\frac{-5\±35.85}{2\times1}= \frac{-5\±35.85}{2}$

Now we will find 2 roots we get;

$l= \frac{-5+35.85}{2}= \frac{30.85}{2}\approx15.425\\\\OR\\\\l =\frac{-5-35.85}{2}= \frac{-40.85}{2} \approx -20.425$

Now we get 2 values of length one is positive and other is negative.

But length of parking lot cannot be negative hence we will discard the negative value.

Hence the length of the parking lot = 15.425 yards

Width of the rectangular parking lot = $l+5=15.425+5 =20.425$

Hence we can say that dimension of parking lot is approximately 15.425 × 20.425 yards.

3 0

3 years ago

Whats the solutions!?? look at the picture

gtnhenbr [62]

Answer:

3/x=y

Step-by-step explanation:

if not am sorry

6 0

3 years ago

A rectangular garden 50 feet long and 10 feet wide is enclosed by a fence. To make the garden larger, while using the same fence

ivann1987 [24]

The area of the rectangular garden is 50 x 10 = 500 square feet.

The perimeter of the rectangular garden is 50 + 50 + 10 +10 =120 feet.

The perimeter of the square also needs to be 120 because it is using the same amount of fence.

Divide 120 by 4 sides: 120/4 = 30

Each side of the square garden would need to be 30 feet.

The area of a square is Side^2, 30^2 = 900 square feet.

The square is 900 - 500 = 400 square feet more.

3 0

3 years ago

Read 2 more answers

Does anyone know how to solve this?

Olin [163]

Answer:

the answer for first question is $112.

the answer for second question is 16 trips.

Step-by-step explanation:

Hope it helps you!!

4 0

3 years ago

Read 2 more answers