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wlad13 [49]
3 years ago
10

What is the slope of the line that contains the points (-1, 2) and (4, 3)?

Mathematics
1 answer:
Vika [28.1K]3 years ago
6 0

Answer:

Slope: 1/5

Step-by-step explanation:

-1,2

4,3

-1 - 2 = -1

-1 - 4 = -5

-1/-5 = 1/5

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On a recent trip, Juan started at an elevation of 1200 feet above sea level. He descended into a valley 20.4 feet below sea leve
liraira [26]

A would be the correct answer because he is up in elevation so that makes the 1200 positive and he goes down 20.4 which is negative and is goes that far down!!

hope this helps

3 0
3 years ago
Read 2 more answers
If FE measures 20 centimeters, the approximate area of circle B is what
MAXImum [283]

If FE measures 20 cm, then the area is 314 cm², if BE measure 3.5 cm, then the area is 38.5 cm², if AB measures 11 cm, then the area is 380 cm² and is EF measures 12 cm, then the area is 113 cm².

Area of a circle:

A = π r²

r = 1 /2 of diameter.

FE is the diameter

r = 20 / 2

r = 10 cm

Area of circle using FE:

A =  π ( 10 )² = π × 100 = 314 cm²

BE is a radius:

Area = π × 3.5² = π × 12.25 = 38.465

A = 38.5 cm²

AB is a radius:

Area = π × 11²
A = π × 121

A = 379.94 = 380 cm²

EF is a diameter:

r = 12 / 2 = 6 cm

Area = π × 6²

A = π × 36

A = 113.04 = 113 cm²

Therefore, if FE measures 20 cm, then the area is 314 cm², if BE measure 3.5 cm, then the area is 38.5 cm², if AB measures 11 cm, then the area is 380 cm² and is EF measures 12 cm, then the area is 113 cm².

Learn more about area here:

brainly.com/question/25292087

#SPJ9

Your question was incomplete, Please refer the content below:

1) if FE measures 20 centimeters, the approximate area of circle B is what?

2) if BE measures 3.5 centimeters, the approximate area of circle B is what?

3) if AB measures eleven centimeters, the approximate area of circle B is what

4) If EF measures twelve centimeters, the approximate area of circle B is what?

6 0
1 year ago
If the mass of a proton is 2.53 x 10^-37 gram, what is the mass of 1,000 protons
Dmitrij [34]
We can solve this problem by the rule of three.

1000 protons=10³ protons

1 proton------------------2.53*10⁻³⁷g
10³ protons----------   x

x=(10³ protons  *   2.53*10⁻³⁷) / 1 proton=2.53*10⁻³⁷⁺³ protons=
=2.53*10⁻³⁴ protons

answer: 2.53*10⁻³⁴ protons
3 0
3 years ago
Find the maximum value or minimum value for the function f(x) = 0.15(x + 1)² - 3.
il63 [147K]

Answer:

The minimum value for  f(x) = 0.15(x + 1)^2 - 3 is -3.

Step-by-step explanation:

Given function is f(x) = 0.15(x + 1)^2 - 3

We need to find the maximum value or the minimum value for the function.

Now, differentiate f(x) = 0.15(x + 1)^2 - 3  w.r.t x.

f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\

f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)

Now, we will equate f'(x)=0 to find critical point.

0.3(x+1)=0\\x=-1

Plug this critical point in to the function f(x) = 0.15(x + 1)^2 - 3  we get,

f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3

Also, f''(x)=0.3 which is positive, We have minimum value.

So, the minimum value for  f(x) = 0.15(x + 1)^2 - 3 is -3.

7 0
3 years ago
Answer all five questions below
Svetach [21]

Answer:

use a calculator

Step-by-step explanation:

there for question b

6 0
3 years ago
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