<span>Sqrt(5x) * Sqrt(x) + 3
= 5^(1/2) * x^(1/2) * x^(1/2) + 3
= 5^(1/2) *x +3
=5^(1/2)*x^(2/2) +3
=Sqrt(5*x^2) +2
So the answer is A </span>
Whole number is 3
Integer but not whole is 1/2
Rational Number is 49/7
Irrational Number is 89/10
The area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.
<h3>How to find the area of a sector?</h3>
1) The formula for area of a sector of a circle is;
A = (θ/360) * πr²
where πr² is area of circle
θ is the angle subtended by the sector
Thus, we conclude that the area of the sector is found by multiplying the area of the circle and the ratio of the angle subtended (measure of the central angle) by the sector to 360.
2) The area of the triangle formed as part of the segment is subtracted from from the area of the sector.
Read more about Area of Sector at; brainly.com/question/22972014
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If the smaller number is x, then the larger number has to be 20 - x in order for the arithmetic mean to be 10, as their sum must be 20.
If the geometric mean is 8 the product of the numbers has to be 64 and so the larger number is 64/x
Solving 64/x = 20 - x gives the quadratic x^2 -20x +64 = 0 so x = 4 or 16.
The two numbers are 4 and 16.
