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Alja [10]
2 years ago
15

9. What four consecutive integers have a sum of -34?

Mathematics
1 answer:
givi [52]2 years ago
4 0

Given,

The four numbers are consecutive

The numbers are

x

x + 1

x + 2

x + 3

Sum = -34

x + (x + 1) + (x + 2) + (x + 3) = -34

x + x + 1 + x + 2 + x + 3 = -34

(x + x + x) + (1 + 2 + 3) = -34

3x + 6 = -34

3x = -34 - 6

3x = -40

x = -40/3

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First, expand to remove parentheses.
4x + 12 = 6 - x
Second, subtract '6' from both sides.
4x + 12 - 6 = -x
Third, subtract '12 - 6' to get 6.
4x + 6 = -x
Fourth, subtract '4x' from both sides.
6 = -x - 4x
Fifth, since 'x' can be referred to as '1', add it to '4x' to get '-5x'.
6 = -5x
Sixth, divide both sides by '-5'.
\frac{6}{-5} =x
Seventh, change the whole fraction into a negative.
-\frac{6}{5} =x
Eighth, switch your sides.
x =  -\frac{6}{5}

Answer as fraction: -\frac{6}{5}
Answer as decimal: -1.2

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Evaluate (-A)2 for A = 5, B = -4, and C = 2.<br> 0-5<br> 0-25<br> 25<br> Help please
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