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gayaneshka [121]
3 years ago
8

Help me guys. plz no Decimal please. Thank you!

Mathematics
1 answer:
Scrat [10]3 years ago
8 0

Answer: 1,145,375cm^3

Step-by-step explanation:

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Which point is on the graph ofx=13(y−18)in the coordinate plane?
natulia [17]

The points on a graph are the points that lie on the graph

The ordered pair on the graph of \mathbf{x =\frac{1}{3}(y - \frac 18)} would be \mathbf{( \frac{5}8},2)

<em>The points are not given; so, I will give a general explanation</em>

The equation is given as:

\mathbf{x =\frac{1}{3}(y - \frac 18)}

Assume that the value of y, is 2

The equation becomes

\mathbf{x = \frac 13(2 - \frac 18)}

Take LCM

\mathbf{x = \frac 13(\frac{16-1}8)}

\mathbf{x = \frac 13(\frac{15}8)}

Divide

\mathbf{x = \frac{5}8}

So, the ordered pair would be \mathbf{( \frac{5}8},2)

Read more about graphs and ordered pairs at:

brainly.com/question/12716270

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2 years ago
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sweet-ann [11.9K]
The answer for this question is -1
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3 years ago
Witch of theese is a composite number 61,71,81,101?
borishaifa [10]
81 is a composite number because it is the only number in the list that is not prime and is divisible by smaller primes.
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3 years ago
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mihalych1998 [28]

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Step-by-step explanation:

8 0
3 years ago
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Write 6(x – 5)4 + 4(x – 5)2 + 6 = 0 in the form of a quadratic by using substitution
abruzzese [7]

Hello from MrBillDoesMath!


Answer:    6 u^2 + 4u + 6 = 0 where u = (x-5)^2


Discussion; I think the problem statement should actually be to rewrite <u>this</u> equation:

6 (x-5)^4 + 4 (x-5)^2 + 6 -= 0.


Note  the power of "x-5" is 4 in the first term and is 2 in the second term. That is, the power of x-5 in the first terms is double, or the square, of the (x-5) power occurring in the second term. This suggest the substitution u = (x-5)^2.  Then the equation can be rewritten as

6 u^2 + 4u + 6 = 0

which is a quadratic in "u".


Regards, MrB


4 0
3 years ago
Read 2 more answers
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