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VikaD [51]
3 years ago
5

What is the answer to this question really need the answer

Mathematics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

A, B, D

Step-by-step explanation:

2 x 3x =6x - 2 times 9y which equals 18y+ and 2 times 18 equals 36 so 2(3x-9y+18)

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marta [7]

Answer:

no solution

Step-by-step explanation:

no solution    x=0

4 0
3 years ago
I NEED HELP ASAP!! WILL GET 15 POINTS FOR THE CORRECT ANSWER!!!
Elanso [62]
All real numbers such that y is greater than 3/17 or y>3/17. Hope this helps!!!!

7 0
4 years ago
Jane says that she can use addition to show that the graphs of 2x - 3y = 1 and 2x + 3y = 2 are intersecting lines. In two or mor
iogann1982 [59]
For this case we have the following equations:
 2x - 3y = 1
 2x + 3y = 2
 When adding both equations we observe that:
 Sentence 1: we have an equation of a variable, which in this case will be x. We can clear the value of x.
 Sentence 2: Knowing the value of x, we can substitute in any equation and find the value of y.
 Sentence 3: The value of x and y represents the point of intersection of both lines (x, y).
4 0
3 years ago
. Mrs. Rojas deposited $8000 into an account paying 4% interest annually. After 8 months Mrs. Rojas withdrew the $6000 plus inte
Mashcka [7]

well, keeping in mind that a year has 12 months, that means that 8 months is 8/12 of a year, when Mrs Rojas pull her money out.

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\to \frac{8}{12}\dotfill &\frac{2}{3} \end{cases} \\\\\\ A=6000[1+(0.04)(\frac{2}{3})]\implies A=6000\left( \frac{77}{75} \right)\implies A=6160

well, she put in 6000 bucks, got back 160 extra, that's the interest earned in the 8 months.

what if she had left her money for 1 whole year, then

~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$6000\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &1 \end{cases} \\\\\\ A=6000[1+(0.04)(1)]\implies A=6240

so had she left it in for a year, she'd have gotten 6240, namely 240 in interest, well, what fraction of a year's interest was earned? or worded differently, what fraction is 160(8 months) of 240(1 year)?

\cfrac{\stackrel{\textit{for 8 months}}{160}}{\underset{\textit{for 12 months}}{240}}\implies \cfrac{2}{3}

4 0
2 years ago
Can Someone help me in this?
My name is Ann [436]

Answer:

You should ask your teacher for help and pay attention in class

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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