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3 years ago

There are (3^2)^4 ⋅ 3^0 bacteria in a petri dish. what is the total number of bacteria in the dish?

Mathematics

2 answers:

sladkih [1.3K]3 years ago

7 0

keepiing in mind that anything raised to 0, is 1, with the sole exception of 0 itself.

$\bf (3^2)^4\cdot 3^0\implies 3^{2\cdot 4}\cdot 1\implies 3^8\implies 6561$

tamaranim1 [39]3 years ago

6 0

3^24 hope this helps because (3^2)^4 make this four times and that means it's 3^24 and you can't multiply it because it's 0 answer is 3^24

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Please help me on this!

yanalaym [24]

Answer:

${9}^{ - 8}$

Step-by-step explanation:

$\frac{ {9}^{ - 5} }{ {9}^{3} }$

${9}^{ - 5 - (3)}$

${9}^{ - 5 + (- 3)}$

${9}^{ - 8}$

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3 years ago

Change each phrase into an algebraic expression

maks197457 [2]

Answer:

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2 years ago

Which word describes the unit price

Pavlova-9 [17]

The last one is right because it’s per 1 unit or in this case day

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2 years ago

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plzzzz help! Determine the truth value of the statement. If three sides of one triangle are equal to three sides of another tria

Tamiku [17]

True that would make it congruent

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3 years ago

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Prove the divisibility of the following numbers:

ratelena [41]

Make use of prime factorizations:

$16^5+2^{15}=(2^4)^5+2^{15}=2^{20}+2^{15}$

Both terms have a common factor of $2^{15}$ :

$16^5+2^{15}=2^{15}\left(2^5+1\right)=2^{15}\cdot33$

- - -

The second one is not true! We can write

$15^7+5^{13}=(3\cdot5)^7+5^{13}=3^7\cdot5^7+5^{13}$

Both terms have a common factor of $5^7$ :

$15^7+5^{13}=5^7\left(3^7+5^6\right)$

Since $30=5\cdot6$ , and $5\mid5^7$ , we'd still have to show that $5^6(3^7+5^6)$ is a multiple of 6. This is impossible, because $6=3\cdot2$ and there is no multiple of 2 that can be factored out.

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3 years ago

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