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Liono4ka [1.6K]
3 years ago
5

Plss help it’s for homework

Mathematics
1 answer:
Zielflug [23.3K]3 years ago
6 0

Answer:

4---- 135

5-----405

6-----1215

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This table gives a few (x,y) pairs of a line in the coordinate plane what is the y-intercept of the line (16,44) (24,64) (32,84)
lapo4ka [179]

Answer:

4

Step-by-step explanation:

find the equation of the line:

slope = rise / run

rise is 20, run is 8

20/8 = 5/2

slope intercept form is y = mx + b

where m is slope and b is y int

y = 5/2(x) + b

use a point given to find b

44 = 5/2(16) + b

44 = 40 + b

b = 4

5 0
4 years ago
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When subtracting 8.7 from a certain number, the result is 22.95, as seen below. What number should go in the box to complete the
Anton [14]
31.65 should go into the box to complete the subtraction problem.
8 0
3 years ago
Some day help me with this 2 question?
gregori [183]

Answer:

As x approaches 0, f(x)=2

Step-by-step explanation:

First plug in f(x) and f(0) into the limit.

\lim_{x \to 0\0} 2x^2+1-(2(0^2)+1)/x^2\\\\, simplify things a bit

\lim_{x \to \ 0} 2x^2/x^2,   divide by x^2

\lim_{x \to \ 0} 2/1=2, as x approaches 0, f(x)=2

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4 years ago
PLEASE HURRY AND HELP WILL GIVE BRAINLIEST!!
mamaluj [8]

Using the given equation:

10PI/X = 240/360

Cross multiply:

(10PI*360) = (240*X)

3600PI = 240X

Divide both sides by 240:

X = 3600PI / 240

X = 15PI in^2

3 0
3 years ago
<img src="https://tex.z-dn.net/?f=5x-%20%5Cdfrac%7B%20%5Csqrt%7B%209%20%7B%20x%20%7D%5E%7B%202%20%7D%20-6x%2B1%20%5Cphantom%7B%5
Morgarella [4.7K]

Answer:

=5x+1          or          =5x-1

Step-by-step explanation:

One is given the following equation:

5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

The problem asks one to simplify the expression, the first step in solving this equation is to factor the equation.  Rewrite the numerator and denominator of the fraction as the product of two expressions. Remember the factoring patterns:

(a-b)^2=a^2-2ab+b^2

=5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}

=5x-\frac{\sqrt{(3x-1)^2}}{-(3x-1)}

Now simplify the numerator. Remember, taking the square root of a squared value is the same as taking the absolute value of the expression,

=5x-\frac{\sqrt{(3x-1)^2}}{1-3x}

=5x-\frac{|3x-1|}{-(3x-1)}

Rewrite the expression without the absolute value sign in the numerator. Remember the general rule for removing the absolute value sign:

|a-b|\\=a -b           or           (-a-b) = b-a

=5x-\frac{|3x-1|}{-(3x-1)}

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

Simplify both expressions, reduce by canceling out common terms in both the numerator and the denominator,

=5x-\frac{3x-1}{-(3x-1)}          or          =5x-\frac{-(3x-1)}{-(3x-1)}

=5x-(-1)          or          =5x-(1)

Simplify further by rewriting the expression without the parenthesis, remember to distribute the sign outside the parenthesis by the terms inside of the parenthesis; note that negative times negative equals positive.

=5x-(-1)          or          =5x-(1)

=5x+1          or          =5x-1

6 0
3 years ago
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