To calculate elapsed time:
Count on in minutes from the earlier time to the nearest hour.
Count on in hours to the hour nearest to the later time.
Count in minutes to reach the later time.
The gap from 9:25 PM to 10 PM is 35 min. The gap from 6 AM to 6:15 AM is 15 min. So far, that accounts for 35+15 = 50 min. The gap from 10 PM to midnight is 2 hours (10+2 = 12). Then the gap from midnight to 6 AM is 6 hours. So we have 2+6 = 8 hours. Add on the minute portion we computed to get 8 hours, 50 minutes.
Answer: 8 hours, 50 minutes
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Answer:
x = - 4 y = - 4
Step-by-step explanation:
x+y= - 8
-9x-6y=60
First, solve for x in the first equation:
x+y = - 8 Subtract y from both sides
x + y - y = -8 - y y cancels on the left
x = - 8 - y
Now plug in what you found for x into the 2nd equation and solve for y.
- 9x - 6y = 60
-9(- 8 - y) - 6y = 60 Multiply out
72 + 9y - 6y = 60
72 + 3y = 60 Subtract 72 from both sides
72 - 72 + 3y = 60 - 72 72 cancels on the left
3y = - 12 Divie both sides by 3
3y/3 = -12/3 3 cancels on the left because 3/3 = 1
y = -4
Now plug your answer for y back into the first equation to get x.
x + y = -8
x + (-4) = - 8 Add 4 to each side
x - 4 + 4 = - 8 + 4 4 cancels on the left
x = -4
x = - 4 and y = - 4
It will take 0.4 seconds to get to the home plate.
Given:
The speed of the pitch thrown by Justin is 100 miles per hour
The distance of home plate from the pitching rubber is 60.5 feet
To find:
The time taken by a pitch to reach the home plate
Solution:
The distance home plate from the pitching rubber = d = 60.5 feet

The speed of pitch thrown by Justin = s = 100 miles/hr
The time taken by a pitch to reach the home plate = t =?
The speed of the moving object is given by dividing the distance covered from the time taken to cover that distance.

In an hour there are 3600 seconds, then in 0.000114583 hours will be:

It will take 0.4 seconds to get to the home plate.
Learn more about conversions here:
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Answer:
The amount that would be in the account after 30 years is $368,353
Step-by-step explanation:
Here, we want to calculate the amount that will be present in the account after 30 years if the interest is compounded yearly
We proceed to use the formula below;
A = [P(1 + r)^t-1]/r
From the question;
P is the amount deposited yearly which is $4,500
r is the interest rate = 2.5% = 2.5/100 = 0.025
t is the number of years which is 30
Substituting these values into the equation, we have;
A = [4500(1 + 0.025)^30-1]/0.025
A = [4500(1.025)^29]/0.025
A = 368,353.3309607034
To the nearest whole dollars, this is;
$368,353
8x + 2 > 34
Subtract 2 from both sides to start isolating x
8x > 32
Divide both sides by 8 to isolate x
x > 4
x is greater than 4