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3 years ago

Find the sum. Write your answer in standard form.

1 answer:

5 0

(4x3+2x+6)+(2x3-x2+2)

Final result :

6x3 - x2 + 2x + 8
Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2". 2 more similar replacement(s).

Step by step solution :

Step 1 :

Equation at the end of step 1 :

(((4•(x3))+2x)+6)+((2x3-x2)+2)
Step 2 :

Equation at the end of step 2 :

((22x3 + 2x) + 6) + (2x3 - x2 + 2)
Step 3 :

Checking for a perfect cube :

3.1 6x3-x2+2x+8 is not a perfect cube

Trying to factor by pulling out :

3.2 Factoring: 6x3-x2+2x+8

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 2x+8
Group 2: 6x3-x2

Pull out from each group separately :

Group 1: (x+4) • (2)
Group 2: (6x-1) • (x2)

You might be interested in

PLEASE HELP-

Deffense [45]

Answer:

1492.88

Step-by-step explanation:

V = πr^2 h/3

3.14 × 18^2

3.14 × 324 = 1017.36

1017.36 × 4.4 = 4476.384

4476.384 ÷ 3 = 1492.88

Hope this helped.

5 0

3 years ago

81x-27=81x−27 what is the answer

kykrilka [37]

The answer is all real numbers for x

because simplifying, you get both sides are equal

5 0

2 years ago

Read 2 more answers

A common blood test performed on pregnant women to screen for chromosome abnormalities in the fetus measures the human chorionic

goldfiish [28.3K]

Answer:

(a) The proportion of women who are tested, get a negative test result is 0.82.

(b) The proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

Step-by-step explanation:

The Bayes' theorem states that the conditional probability of an event E $_{i}$ , of the sample space S, given that another event A has already occurred is:

$P(E_{i}|A)=\frac{P(A|E_{i})P(E_{i})}{\sum\liits^{n}_{i=1}{P(A|E_{i})P(E_{i})}}$

The law of total probability states that, if events E₁, E₂, E₃... are parts of a sample space then for any event A,

$P(A)=\sum\limits^{n}_{i=1}{P(A|B_{i})P(B_{i})}$

Denote the events as follows:

X = fetus have a chromosome abnormality.

Y = the test is positive

The information provided is:

$P(X)=0.04\\P(Y|X)=0.90\\P(Y^{c}|X^{c})=0.85$

Using the above the probabilities compute the remaining values as follows:

$P(X^{c})=1-P(X)=1-0.04=0.96$

$P(Y^{c}|X)=1-P(Y|X)=1-0.90=0.10$

$P(Y|X^{c})=1-P(Y^{c}|X^{c})=1-0.85=0.15$

(a)

Compute the probability of women who are tested negative as follows:

Use the law of total probability:

$P(Y^{c})=P(Y^{c}|X)P(X)+P(Y^{c}|X^{c})P(X^{c})$

$=(0.10\times 0.04)+(0.85\times 0.96)\\=0.004+0.816\\=0.82$

Thus, the proportion of women who are tested, get a negative test result is 0.82.

(b)

Compute the value of P (X|Y) as follows:

Use the Bayes' theorem:

$P(X|Y)=\frac{P(Y|X)P(X)}{P(Y|X)P(X)+P(Y|X^{c})P(X^{c})}$

$=\frac{(0.90\times 0.04)}{(0.90\times 0.04)+(0.15\times 0.96)}$

$=0.20$

Thus, the proportion of women who get a positive test result are actually carrying a fetus with a chromosome abnormality is 0.20.

6 0

3 years ago

A General Motors buyer-incentive program offered a 5.5% rebate on the selling price of a new car. What rebate (in dollars) would

Mashcka [7]

Answer: he would receive a rebate of $1677.5

Step-by-step explanation:

A General Motors buyer-incentive program offered a 5.5% rebate on the selling price of a new car. This means that if the selling price of the new car is $x, the rebate (in dollars) that a customer would receive is

5.5/100 × x = 0.055 × x = 0.055x

Therefore, for a customer who purchased a $30,500 car under this program, the rebate that he would receive is

0.055 × 30500 = $1677.5

6 0

3 years ago

Use the table to find the ratio. Enter the ratio as a fraction in simplest form.

snow_tiger [21]

Answer:

4/19

Step-by-step explanation:

8 0

2 years ago