Hmm I’ve done this before but I can’t remember sorry but I will try and think
Answer:
p^2 + q^2 = 22/9.
Step-by-step explanation:
For a quadratic function ax^2 + bx + c if the zeroes are A and B then
A + B = -b/a and AB = c/a.
2x^2 - 7x + 3
Now p and q are the zeroes of the above function so
p + q = 7/3 and pq = 3/2.
Now p^2 + q^2 = (p + q)^2 - 2pq
= (7/3)^2 - 2* 3/2
= 49/9 - 3
= 49/4 - 27/9
= 22/9.
(a) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.11 + 0.52 + 0.19 = 0.82
(b) P(X ≥ 1) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.52 + 0.19 + 0.12 + 0.06 = 0.89
(c) µ = 0×0.11 + 1×0.52 + 2×0.19 + 3×0.12 + 4×0.06 = 1.5
(d) σ² = (0²×0.11 + 1²×0.52 + 2²×0.19 + 3²×0.12 + 4²×0.06) - µ² = 1.07
σ = √(σ²) ≈ 1.03
Rate of change = difference in y over difference in x.
Rate of change = (33-20)/(3-1) = 13/2
Rate of change = (48-33) /(5-3) = 15/2
The rates are not the same so it isn’t linear.
The rate of change for x=3 and x = 5 is greater.
