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Neporo4naja [7]
3 years ago
12

In the earlier Lesson Activity, you found the sizes of mesoplankton and jellyfish. In this activity, you’ll determine the most a

ppropriate units for measuring the sizes of mesoplankton and jellyfish.
Part B
You also found the size of a jellyfish to be 2 meters. Do you think that meters are the most appropriate unit to represent the size of a jellyfish? If not, what do you think would be the most appropriate unit? Write the size of the jellyfish in the most appropriate unit.
Mathematics
1 answer:
damaskus [11]3 years ago
3 0

Answer:

We did not read the lesson so we dont kown

I can answer the seocnd question i think no because as meters may be to small for some jellyfish as they come in diffrence sizes so i think millimeter are the prefect size.

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What is an equation of the line that passes through the points ( 0,-7) and ( 5, -1)
tresset_1 [31]

Answer:

y = 5/6x - 5.167

Or

y = 5/6x - 31/6

Step-by-step explanation:

The equation of a line

y = mx + c

Step 1: find the slope

m = y2 - y1 / x2 - x1

Given points

( 0 , -7) ( 5 , -1)

x1 = 0

y1 = -7

x2 = 5

y2 = -1

Insert the values into the equation

m = -1 - (-7) / 5 - 0

m = -1 + 7 / 5

m = 6/5

y = 6/5x + c

Step 2: sub any of the two points given into the equation

y = 5/6x + c

( 5 , -1)

x = 5

y = -1

-1 = 5/6(5) + c

-1 = 5*5/6 + c

-1 = 25/6 + c.

c = -1 - 25/6

LCM = 6

c = -6 - 25 / 6

c = -31/6

c = -5.167

Step 3: sub c into the equation

y = 5/6x + c

y = 5/6x - 31/6

Or

y = 5/6x - 5.167

The equation of the line is

y = 5/6x - 5.167

7 0
3 years ago
Find the slope of the tangent line to the curve f(x)=e^(x) at (0.4,1.49)
almond37 [142]

Answer:

1.49

Step-by-step explanation:

In order to find the slope of the tangent line to a given equation, and in a given point, we need to:

1. Find the first derivative of the given function.

2. Evaluate the first derivative function in the given point.

1. Let's find the first derivative of the given function:

The original function is f(x)=e^{x}

But remeber that the derivative of  e^{x} is  e^{x}

so, f'(x)=e^{x}

2. Let's evaluate the first derivative function in the given point

The given point is (0.4,1.49) so:

f'(x)=e^{x}

f'(0.4)=e^{0.4}

f'(x)=1.49

Notice that the calculated slope of the tangent line is equal to the y-coordinate of the given point because f'(x)=f(x). In conclusion, the slope of the tangent line is equal to 1.49.

8 0
3 years ago
Y=2x+7<br> y−2x=7<br> how many solutions does it have
quester [9]

Answer: Many solutions!

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
W(x) = 3x; find (-3x)
Mashutka [201]
So this means W(-3x) = 3x. So it's equal to 3(-3x), which simplifies to be -9x. Whenever you have a function, it looks like f(x). f doesn't have to be the letter, it can be a, b, c, or like in this case, W. It just means the output of what W(x) is if x equals the number in the parentheses, which is -3x in this case.
7 0
3 years ago
Hey anybody able to help? Which expression is equivalent to -5(3x-6/7)?
nalin [4]

Answer:

A: - 15x - 30/7

Step-by-step explanation:

-5 (3x - 6/7)

Just distribute -5 to the values inside the parentheses.

-5 · 3x = -15x

-5 · 6/7 = -30/7

Now form it together:

-15x - 30/7

7 0
3 years ago
Read 2 more answers
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