Answer:
answer d
Step-by-step explanation:
I took the assignment and got it right :)
<span>f(x) = one eighth (x - 2)^2 - 1
Since a parabola is the curve such that all points on the curve have the same distance from the directrix as the distance from the point to the focus.With that in mind, we can quickly determine 3 points on the parabola. The 1st point will be midway between the focus and the directrix, So:
(2, (1 + -3)/2) = (2, -2/2) = (2,-1).
The other 2 points will have the same y-coordinate as the focus, but let offset on the x-axis by the distance from the focus to the directrix. Since the distance is (1 - -3) = 4, that means the other 2 points will be (2 - 4, 1) and (2 + 4, 1) which are (-2, 1) and (6, 1). The closest point to the focus will have the same x-coordinate as the focus, so the term will be (x-2)^2. This eliminates the functions "f(x) = -one eighth (x + 2)^2 - 1" and "f(x) = -one half (x + 2)^2 - 1" from consideration since their x term is incorrect, leaving only "f(x) = one eighth (x - 2)^2 - 1" and "f(x) = one half (x - 2)^2 + 1" as possible choices. Let's plug in the value 6 for x and see what y value we get from squaring (x-2)^2. So:
(x-2)^2
(6-2)^2 = 4^2 = 16
Now which option is equal to 1? Is it one eighth of 16 minus 1, or one half of 16 plus 1?
16/8 - 1 = 2 - 1 = 1
16/2 + 1 = 8 + 1 = 9
Therefore the answer is "f(x) = one eighth (x - 2)^2 - 1"</span>
Answer:
5.4
Answer: The value of x rounded to the nearest tenth is 5.4.
Step-by-step explanation:
Answer:
a.(x+5)(x-5) b.(y+6)(y-6) c.(x-1)(x+13) d. (s+2)(s+5)
Step-by-step explanation:
Sorry no step for c and d
for a 25 is a perfect square 5*5=25 -5*5=-25
for b it's same
sorry I'm rushing
Answer:
MN and 170°
Step-by-step explanation:
to get around the red arc you would go alphabetically to the points M, N. since u already have 170° and a circles full rotation is 360° that means 360-170=190 and so the blue arc of the circle would either have to be 190° or 170°, and since the angle of the blue arc is farther than the red arc, that would mean the blue arc is 190°.