Answer:
531.167 ft²
Step-by-step explanation:
Given data
Dimension of pool
Diameter =24ft
Radius =12ft
If the cover must hang by 1ft around, then the diameter is 26ft
Radius =13ft
Area of cover = πr²
Substitute
Area = 3.142*13²
Area =3.143*169
Area =531.167 ft²
Hence the minimum area is 531.167 ft²
We can solve this using substitution.
because x-y=2.5
x=y+2.5
Now substitute x into other equation.
2(y+2.5)^2-2y=125
2y^2+10y+12.5-2y=125
2y^2+8y-112.5=0
Now comes the ugly part
y=-4+-sqrt(16+900)
y=-4+-sqrt916
y=-4+-2sqrt229
x=-1.5+-2sqrt229
Answer:
Volume of the tank = 636 ft³
Step-by-step explanation:
Formula for the volume of a cylinder is,
V = πr²h
Where r = radius of the cylinder
h = height of the cylinder
By substituting the values of radius and height of the water tank given in the question,
V = 
= 202.5π
= 202.5 × (3.14)
= 635.85 ft³
≈ 636 ft³
Therefore, volume of the cylindrical water tank is 636 ft³.
Cicumference = Dπ or 2rπ
thus if r = 2.2
then C = 2 (2.2)π
= 4.4π
D is the answer