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Mrrafil [7]
3 years ago
15

Write 16 cookies to 30 brownies as a ratio in simplest form. Use a ":" in your answer.

Mathematics
2 answers:
andriy [413]3 years ago
5 0

Answer:

  1. 8:15

Step-by-step explanation:

16:30 simplify by reducing both numbers twice

Rudik [331]3 years ago
4 0

Answer:

  • 8 : 15

Step-by-step explanation:

<u>Ratio of cookies to brownies:</u>

  • 16 : 30 =   simplify by reducing both numbers twice (the only common  factor)
  • 8 : 15
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Cereal A cost. $4.20 for a 14-ounce box and Cereal B costs $3.90 for a 12-ounce box. Which is better?
antiseptic1488 [7]
Cereal A is a better option...Need an explanation?
3 0
4 years ago
Read 2 more answers
Two ships leave the same port in different directions, forming a 120° angle between them. One ship travels 70 mi. and the other
kondaur [170]

Answer : Distance between the ships to the nearest miles = 106.03 ≈ 106 mi.

Explanation :

Since we have shown in the figure below :

a=70 mi.

b=52 mi.

c=x mi.

\text{Since two ships leaves the same port in different directions forming a }120\textdegree\text{angle between them.}

So, we use the cosine rule , which states that

 c^2=a^2+b^2-2ab.cosC\\\\x^2=70^2+52^2-2\times 70\times 52\times cos(120\textdegree)\\\\x^2=4900+2704-7280\times (-0.5)\\\\x^2=7604+3640\\\\x^2=11244\\\\x=\sqrt{11244}\\\\x=106.03

So, c = x= 106.03 mi.

Hence, distance between the ships to the nearest miles = 106.03 ≈ 106 mi.


8 0
3 years ago
There is 2 questions and I would like time to answer both of them! Please and thank you!
morpeh [17]
#1 is b and #2 is also b ,, i think..so sorry if i’m wrong!
4 0
3 years ago
Read 2 more answers
What is the sum of the first 51 consecutive odd positive integers?
Angelina_Jolie [31]
We call:

a_{n} as the set of <span>the first 51 consecutive odd positive integers, so:

</span>a_{n} = \{1, 3, 5, 7, 9...\}

Where:
a_{1} = 1
a_{2} = 3
a_{3} = 5
a_{4} = 7
a_{5} = 9
<span>and so on.

In mathematics, a sequence of numbers, such that the difference between two consecutive terms is constant, is called Arithmetic Progression, so:

3-1 = 2
5-3 = 2
7-5 = 2
9-7 = 2 and so on.

Then, the common difference is 2, thus:

</span>a_{n} = \{ a_{1} , a_{1} + d, a_{1} + d + d,..., a_{1} + (n-2)d+d\}
<span>
Then:

</span>a_{n} = a_{1} + (n-1)d
<span>
So, we need to find the sum of the members of the finite series, which is called arithmetic series:

There is a formula for arithmetic series, namely:

</span>S_{k} = ( \frac{a_{1} +  a_{k}}{2}  ).k
<span>
Therefore, we need to find:
</span>a_{k} =  a_{51}  

Given that a_{1} = 1, then:

a_{n} = a_{1} + (n-1)d = 1 + (n-1)(2) = 2n-1

Thus:
a_{k} = a_{51} = 2(51)-1 = 101

Lastly:

S_{51} = ( \frac{1 + 101}{2} ).51 = 2601 

4 0
3 years ago
Please help ASAP brainliest.
lisov135 [29]

Answer:

\left[\begin{array}{cc}2&8\\5&1\end{array}\right]

Step-by-step explanation:

The <em>transpose of a matrix </em>M^T is one where you swap the column and row index for every entry of some original matrix M. Let's go through our first matrix row by row and swap the indices to construct this new matrix. Note that entries with the same index for row and column will stay fixed. Here I'll use the notation p_{i,j} and p^T_{i,j} to refer to the entry in the i-th row and the j-th column of the matrices P and P^T respectively:

p_{1,1}=p^T_{1,1}=2\\p_{1,2}=p^T_{2,1}=5\\p_{2,1}=p^T_{1,2}=8\\p_{2,2}=p^T_{2,2}=1\\

Constructing the matrix P^T from those entries gives us

P^T=\left[\begin{array}{cc}2&8\\5&1\end{array}\right]

which is option a. from the list.

Another interesting quality of the transpose is that we can geometrically represent it as a reflection over the line traced out by all of the entries where the row and column index are equal. In this example, reflecting over the line traced from 2 to 1 gives us our transpose. For another example of this, see the attached image!

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3 years ago
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