15^2 + 8^2 = 225 + 64 = 289
square root 289 = 17
answer
<span>length of the hypotenuse of the triangle = 17 cm (3rd choice)</span>
Answer:
The quotient is the result of the division. Thus 3.4 ÷6 =5.6.........
Step-by-step explanation:
Answer:
Number of dolphins in zoo * number of fish per dolphin.
Step-by-step explanation:
Hansen won the raffle At the zoo and gets to feed the dolphins! The dolphin trainer gives Hansen a bucket of fish to divide evenly among five dolphins. Each dolphin gets four fish. Which equation can you use to find the number of fish F in the bucket before hansen feeds them
Given that:
Number of dolphins = 5
Fish in bucket is distributed equally ; hence, Number of fish per dolphin = 4
To obtain the initial number of fish in bucket before hansen began to feed the fishes :
Number of fish in bucket before hansen feeds then :
Number of dolphins in zoo * number of fish per dolphin.
5 * 4 = 20
Answer: for 9 attendees it would cost $18
Step-by-step explanation: First you have to find the unit rate. So for every 7 attendees it costs $14, divide them both by the GCF which is 7. 14÷7=2
7÷7=1
So for every 1 attendee it is $2.
Now to figure out how much it would cost for 9 attendees, figure out what you have to do to 1 to get 9. Multiply it by 9.
And whatever you do to one number you have to do for the other. So $2 • 9 = $18
So for every 9 attendees it costs $18.
I'll explain how to do the first one:-
y = cos-1(x2)
This can be described as ' a function of a function' x^2 is a function of x and cos-1(x^2) is a function of x^2.
We need to apply the chain rule.
Personally I find this easier to understand if i let u = x^2, so
If y = f(u) and u is a function of x then
dy/dx = dy/ du * du/dx
Here u = x^2 and y = cos-1(u)
du/dx = 2x
so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx
= -1 / √(1 - u^2) * 2x
= -2x / √(1 - u^2)
= -2x / √(1 - (x^2)^2)
= -2x / √(1 - x^4)
I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.