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solong [7]
3 years ago
12

Please help me if you know it means a lot thank you

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0

1.5 x -3 +4. x=-3

-15+4

-11

2.-4/4-2 x-4-3. y=-4

-1-+8-3

7-3

4

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PLEASE HELP ASAP
Leona [35]

Answer:

5-rl=5

Step-by-step explanation:

rl=5-5= and anawer is=0

7 0
3 years ago
Find the largest 4-digit number which is a perfect square.
pickupchik [31]

Answer:

<em><u>To find the biggest 4-digit number which is a perfect square, we have to take the square of biggest 2-digit number. ∴ The biggest 4-digit number which is a perfect square = 9801.</u></em>

Step-by-step explanation:

<h2>mark as brainlest answer </h2>
6 0
2 years ago
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the length of a rectangle is 5 cm less than 3 time its width. if the perimeter of the rectangle is 54 cm, find the length and wi
castortr0y [4]

length = 3x - 5 \\ width \:  = x \\ p = 2l + 2w \\ 54 = 2(3x - 5) + 2x \\ 54 = 6x - 10 + 2x \\ 54 = 8x - 10 \\ 64 = 8x \\ x = 8 = width \\ 3(8) - 5 = 24 - 5 = 19 \\ length = 19
6 0
3 years ago
Suppose we have an unfair coin that its head is twice as likely to occur as its tail. a)If the coin is flipped 3 times, what is
Alenkinab [10]

Answer: a) 0.2222, b) 0.3292, c) 0.1111

Step-by-step explanation:

Since we have given that

Let the probability of getting head be p.

Since,  its head is twice as likely to occur as its tail.

p+\dfrac{p}{2}=1\\\\\dfrac{3p}{2}=1\\\\p=\dfrac{2}{3}

a)If the coin is flipped 3 times, what is the probability of getting exactly 1 head?

So, here, n  = 3

p=\dfrac{2}{3}

q=\dfrac{1}{3}

Now,

P(X=1)=^3C_1(\dfrac{2}{3})^1(\dfrac{1}{3})^2=0.2222

b)If the coin is flipped 5 times, what is the probability of getting exactly 2 tails?

2 tails means 3 heads.

So, it becomes,

P(X=3)=^5C_3(\dfrac{2}{3})^3(\dfrac{1}{3})^2=0.3292

c)If the coin is flipped 4 times, what is the probability of getting at least 3 tails?

P(X\leq 1)=\sum _{x=0}^1^4C_x(\dfrac{2}{3}^x(\dfrac{1}{3})^{4-x}=0.1111

Hence, a) 0.2222, b) 0.3292, c) 0.1111

8 0
3 years ago
Merrill is playing a simple game of dice. For every 6 rolled, Merrill will win $5. For any other number, he must pay $2. How muc
Schach [20]

Solution -

The probability of getting 6 from a single roll of a fair dice = \frac{1}{6}

The probability of getting any other number rather than 6 would be 1-\frac{1}{6} = \frac{5}{6}

So when the outcome is 6, then he wins $5 ,otherwise he has to pay $2

So

E(X) = Expectation value = (\frac{1}{6} )(5) - (\frac{5}{6} )(2)                                    ( ∵ $5 gain so +ve and $2 loss so -ve)

=\frac{-5}{6}

∴ So Merrill will lose \frac{5}{6} dollar


7 0
3 years ago
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