Let V be a vector space, and let v1, v2, v3 and v4 be linearly independent vectors in V . In parts (a) and (b) below, determine
1 answer:
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Join the center of the hexagon with the 2 base angles.
An equilateral triangle, with side length x, is formed.
(remark: a regular hexagon is made up of 6 equilateral triangles with equal length)
The height
forms 2 congruent right triangles with :
hypotenuse= x, side_1=x/2, and side_2=.
From the pythagorean theorem we have:
thus, x=4.
The area of the triangle is 1/2 * 4 *
=6.93 (mm squared)
The area of the hexagon is 6* the area of the triangle = 42 (mm squared)
Answer: a. 42 (mm squared)
An equilateral triangle, with side length x, is formed.
(remark: a regular hexagon is made up of 6 equilateral triangles with equal length)
The height
hypotenuse= x, side_1=x/2, and side_2=
From the pythagorean theorem we have:
thus, x=4.
The area of the triangle is 1/2 * 4 *
The area of the hexagon is 6* the area of the triangle = 42 (mm squared)
Answer: a. 42 (mm squared)
Answer:
C) -3
Step-by-step explanation:
+ 8 = 13
= 5
-5x = 15
x = -3