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Ugo [173]
3 years ago
11

Please help!!!!!!!!! I'll mark brainliest if you give an explanation!!!!

Mathematics
1 answer:
Maru [420]3 years ago
5 0

Answer:

say whaaaaaaaaaaaaaaàaaaaaaaaaaaaattttt??? i dont understand

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How does the graph of f(x)=5 cos(1/2x)-2 differ from the graph of g(x)=5 cos(x)-2
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F(x) = 5cos(1/2x) - 2
g(x) = 5cos(x) - 2

The period for a cosine function is 2pi/k
In the equation the k is  located before the variable.
In g(x) we have 5cos (1x) -2
so the period is 2pi/1 or 2pi. This means the length of one full period of cosine will go from 0 to 2pi.

In f(x) we have 5 cos (1/2 x) - 2
so the period is 2pi/ (1/2) which is the same as 2pi * 2 or 4pi.
This means the period for the function is 4pi and the length of one full period of the cosine graph will go from 0 to 4pi.
The length of f(x) will be longer than that of g(x) .
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2 percent more means that you take 102 percent of the actual reading, 102 percent of 325= 331.5 degrees

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gogolik [260]

The standard form for y=-7+6x is Ax + By = C
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Solve for x, need help!
tatyana61 [14]

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Cosθ =Adjacent / hypotenuse

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Hii please help asap ill give brainliest thanks
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The answer is ayurveda

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