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topjm [15]
2 years ago
6

Darnell's truck can travel 18 miles on 1 gallon of gasoline. How many gallons of gasoline will Darnell need to travel 315 miles?

Use the formula d/m=g, where m represents miles per gallon, d is distance traveled, and g is the number of gallons of gasoline used.
Mathematics
1 answer:
kiruha [24]2 years ago
8 0

Answer: 17.5 gallons

Step-by-step explanation:

The formula to solve this question will be: g = d/m

where, g = number of gallons of gasoline used

d = distance travelled = 315 miles

m = miles per gallon = 18 miles/gallon

Therefore, the number of gallons of gasoline that Darnell will need to travel 315 miles will be:

g = d/m

g = 315/18

= 17.5 gallons

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Which of the following is the graph of f(x) = x2 + 3x − 4?
xenn [34]

Answer:

2nd graph

Step-by-step explanation:

Given

f(x) = x² + 3x - 4

To find the zeros let f(x) = 0 , that is

x² + 3x - 4 = 0 ← in standard form

(x + 4)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 1 = 0 ⇒ x = 1

The only graph with zeros at x = - 4 and x = 1 is the 2nd graph

6 0
2 years ago
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What is straight is part of a line and has 2 endpoints
Yuri [45]
Answer:  Length

Explanation:

<span>straight line with 2 endpoints ====> Length</span>
3 0
3 years ago
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If a phone plan allows for 698 minutes each month, and Jorge uses 475 minutes by the end of the second week, what percent of his
Juli2301 [7.4K]
Well I'm doing it an easy way but 50% or half of 698 is about 350.

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5 0
3 years ago
Mrs. Jackson earned a 500 bonus for signing a one-year contract to work as a nurse. Her salary is 22 per hour. If her first week
jekas [21]
Ok so your first step is to make this an equation
she gets paid x amount per hour and she works for 22 hours
so 22x plus her bonus
22x + 500 =1204
so now solve the equation
subtract both sides by 500
22x +500 =1204
-500 = -500
to get
22x = 704
now divide both sides by 22
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7 0
2 years ago
If f(x)=x^2 and g(x)=1÷2x+3 find g(f(-1))
gogolik [260]

ANSWER

g(f( - 1)) = \frac{1}{5 }

EXPLANATION

The given function is:

f(x) =  {x}^{2}

and

g(x) =  \frac{1}{2x + 3}

g(f(x)) = g( {x}^{2} )

g(f(x)) = \frac{1}{2{x}^{2} + 3 }

To find g(f(-1)), we substitute x=-1, to obtain;

g(f( - 1)) = \frac{1}{2{( - 1)}^{2} + 3 }

We simplify the square in the denominator to get,

g(f( - 1)) = \frac{1}{2+ 3 }

We now add the denominator to obtain;

g(f( - 1)) = \frac{1}{5 }

6 0
3 years ago
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