Answer: A: hours per acre. B. 4 1/8÷2 3/4 C. 4 1/8÷2 3/4=33/8÷11/4
Step-by-step explanation:
Step-by-step explanation:
A reference point is a place or object used for comparison to determine if something is in motion.
Answer:
Hence, 0.0000087 can be expressed as
.
Step-by-step explanation:
- Given 0.00000871
- Move the decimal point so that the factor is greater than or equal to 1 but less than 10 .
- Then count n and write no. as product with a power of 10 .
Step 1 of 1
Consider 0.00000871,
8.71
Decimal has moved 6 places to right.
The power will be negative as the original no. is less than 1 .

Answer:
<em>The solution of the system is:
</em>
Step-by-step explanation:
The given system of equations is.......

So, the augmented matrix will be: ![\left[\begin{array}{cccc}-1&-3&|&-17\\2&-6&|&-26\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%26-3%26%7C%26-17%5C%5C2%26-6%26%7C%26-26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now, we will transform the augmented matrix to the reduced row echelon form using row operations.
<u>Row operation 1 :</u> Multiply the 1st row by -1. So..........
![\left[\begin{array}{cccc}1&3&|&17\\2&-6&|&-26\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%26%7C%2617%5C%5C2%26-6%26%7C%26-26%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<u>Row operation 2:</u> Add -2 times the 1st row to the 2nd row. So.......
![\left[\begin{array}{cccc}1&3&|&17\\0&-12&|&-60\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%26%7C%2617%5C%5C0%26-12%26%7C%26-60%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<u>Row operation 3:</u> Multiply the 2nd row by
. So.......
![\left[\begin{array}{cccc}1&3&|&17\\0&1&|&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%263%26%7C%2617%5C%5C0%261%26%7C%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
<u>Row operation 4:</u> Add -3 times the 2nd row to the 1st row. So........
![\left[\begin{array}{cccc}1&0&|&2\\0&1&|&5\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%26%7C%262%5C%5C0%261%26%7C%265%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Now, from this reduced row echelon form of the augmented matrix, we can get that
and 
So, the solution of the system is: 