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Anna35 [415]
3 years ago
7

Write two shopping scenarios where multi-step equations can be written and solved.

Mathematics
1 answer:
Viefleur [7K]3 years ago
3 0

Scenarios:

She went shopping on friday and spent 102.52$ and began with 201.24, and then on sunday she went again to shop and spent 58.2 and gave her friend 30.23$ to shop with. How much did she spend and how much does she still have.

Andrew went to the store and spent 403.54 on a PS4 and a 4 games, the PS4  costed 330.54 dollars, and the games all were the same price but the last game was 10$ more then the rest of the games, how much were the games?

Step-by-Step explanation:

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Suzanne owns stock worth $2,400. She owes $5,200 in student loans, and $2,500 on a credit car. She owes $1,800 on a car that is
jekas [21]

Answer:

15,100

Step-by-step explanation:

because 5,200+2,500+8,000+1,800=17,500 which is how much she owes and what she has is 2,400 so 17,500- 2,400= 15,100 so her net worth is 15,100

3 0
3 years ago
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
Which graphs show continuous data?<br> Select each correct answer.
Nikolay [14]

Answer:

I say the first graph in the first pic

Also,the 2nd graph in the 2nd pic

7 0
2 years ago
Read 2 more answers
What is the surface area of the box if it is scaled up by a factor of 10? Boxes Dimensions 7in Height 6in Length 2in Width
VladimirAG [237]

Answer:

13,600 in^{2}

Step-by-step explanation:

(h = 7, l = 6, w = 2) 10

70, 60, 20

2(h × w) + 2(h × l) + 2(w × l)

= 2(70 × 20) + 2(70 × 60) + 2(20 × 60)

= 2(1400) + 2(4200) + 2(1200)

= 2800 + 8400 + 2400

= 13,600

4 0
3 years ago
Find the interval(s) of upward concavity on this accumulation function.
maxonik [38]

\displaystylef(x)=\int_{0}^{x^2}\sec^2(\sqrt{x})dx \\=\int_{0}^{\sqrt{x^2}}\sec^2(u)\cdot2udu \\=2\int_{0}^{\sqrt{x^2}}\sec^2(u)du \\=2\Big[u\tan(u)-\int\tan(u)du\Big]_{0}^{\sqrt{x^2}} \\=2\Big[u\tan(u)+\ln\Big(\mathrm{abs}(\cos(u))\Big)\Big]_0^x \\=2\Big(x\tan(x)+\dfrac{1}{2}\ln\Big(\cos^2(x)\Big)\Big) \\=2x\tan(x)+\ln(\cos^2(x))

Hope this helps.

6 0
3 years ago
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