3 years ago

Recursive equation for -2, -5, -8, -11, -14

Mathematics

1 answer:

Minchanka [31]3 years ago

4 0

Answer:

f(0) = 1

f(x) = f(x-1) - 3

Step-by-step explanation:

probably use the style of your teacher

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(a-b)(a^2 + ab + b^2)

Nitella [24]

Answer:

a^3-b^3

Step-by-step explanation:

(a−b)(a2+ab+b2)

=(a+−b)(a2+ab+b2)

=(a)(a2)+(a)(ab)+(a)(b2)+(−b)(a2)+(−b)(ab)+(−b)(b2)

=a3+a2b+ab2−a2b−ab2−b3

=a3−b3

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3 years ago

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arlik [135]

Given:

In a right angle triangle θ is an acute angle and $\tan\theta =\dfrac{3}{5}$ .

To find:

The value of $\cos \theta$ .

Solution:

In a right angle triangle,

$\tan \theta=\dfrac{Perpendicular}{Base}$

We have,

$\tan\theta =\dfrac{3}{5}$

It means the ratio of perpendicular to base is 3:5. Let 3x be the perpendicular and 5x be the base.

By using Pythagoras theorem,

$Hypotenuse=\sqrt{Perpendicular^2+base^2}$

$Hypotenuse=\sqrt{(3x)^2+(5x)^2}$

$Hypotenuse=\sqrt{9x^2+25x^2}$

$Hypotenuse=\sqrt{34x^2}$

$Hypotenuse=x\sqrt{34}$

In a right angle triangle,

$\cos \theta=\dfrac{Base}{Hypotenuse}$

$\cos \theta=\dfrac{5x}{x\sqrt{34}}$

$\cos \theta=\dfrac{5}{\sqrt{34}}$

Therefore, the value of $\cos \theta$ is $\dfrac{5}{\sqrt{34}}$ .

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3 years ago

12x6y-422<br> 2. Which expression is equivalent to<br> 3x2y-623 ?

Viefleur [7K]

Answer:

Step-by-step explanation:

7 0

3 years ago

How do you solve x3 (y-5) (x-8) (the numbers next to the variables (letters) are supposed to be exponents)

Galina-37 [17]

Y^-5
x^-5
because you have to put together all the x and then put all the y's together

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4 years ago

The line below are parallel. If the slope of the green line is 2/7, what is the slope of the red line?

professor190 [17]

Parallel lines have the same slope. So the slope of the other line =2/7

6 0

3 years ago

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