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muminat
3 years ago
5

Which of the following has no solution? 5x−10=x+20 2(6+x)=14+2x 0x+5=3(5x+7) 2(4+x)=8+2x

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0

Answer:

2(6+x)=14+2x

Step-by-step explanation:

There are no solutions

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If c(x) = 4x − 2 and d(x) = x² + 5x, what is (c.d)(x)?
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Answer:

4x^2+20x-2

Step-by-step explanation:

To find (c.g)(x) we basically use the function d(x) as your variable, x, and plug it into c(x). So we replace every x in c(x) with the function d(x), x^{2} +5x

c(g(x))=4(x^{2} +5x)-2

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Write the expression n ⋅ n ⋅ p ⋅ p ⋅ r ⋅ r ⋅ r using exponents.
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n² p²r³

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n ⋅ n ⋅ p ⋅ p ⋅ r ⋅ r ⋅ r

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There are 2 n terms

n²⋅ p ⋅ p ⋅ r ⋅ r ⋅ r

There are 2 p terms

n² p²⋅ r ⋅ r ⋅ r

There are 3 r terms

n² p²r³

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What is the ratio of the area of the inner square to the area of the outer square?
Anastasy [175]

Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

=(\sqrt{(a-b)^2+b^2})^2

=(a-b)^2+b^2\text{ square cm}

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

=\sqrt{(a-0)^2+0^2}

=\sqrt{a^2}=a

Thus, the area of the outer square = (side)²

=a^2\text{ square cm}

Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

4 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP! BRAINLIEST TO BEST/RIGHT ANSER!!
s2008m [1.1K]
The answer is B.) 1/81
8 0
3 years ago
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