A. Y=x+4. B. Y= -2/3x-4. c. Y=-2x+4. d. Y=-1/2x+4 Pls help

in a classroom, 1/6 of the students are wearing blue shirts and 2/3 are wearing white shirts. there are 36 students in the class

Zina [86]

The fraction indicating the number of students who are not wearing either blue or white shirt is:
1- 1/6- 2/3= 1/6.

36 students* (1/6)= 6 students.

There are 6 students who are not wearing either a blue or a white shirt.

Hope this helps~

5 0

3 years ago

6x+3y=15 .What does y equal if x=2 ?if x=5

bezimeni [28]

_Award brainliest if helped!
if x =2 , 6(2) + 3y = 15
3y = 15-12
y = 1
if x=5, 6(5) + 3 y = 15
3y = -15
y= -5

8 0

2 years ago

One measure of an athlete’s ability is the height of his or her vertical leap. Many professional basketball players are known fo

almond37 [142]

Answer:

(1) P( $\bar X$ < 26 inches) = 0.0436

(2) P(27.5 inches < $\bar X$ < 28.5 inches) = 0.2812

Step-by-step explanation:

We are given that the mean vertical leap of all NBA players is 28 inches. Suppose the standard deviation is 7 inches and 36 NBA players are selected at random.

Firstly, Let $\bar X$ = mean vertical leap for the 36 players

Assuming the data follows normal distribution; so the z score probability distribution for sample mean is given by;

Z = $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean vertical leap = 28 inches

$\sigma$ = standard deviation = 7 inches

n = sample of NBA player = 36

(1) Probability that the mean vertical leap for the 36 players will be less than 26 inches is given by = P( $\bar X$ < 26 inches)

P( $\bar X$ < 26) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{26-28}{\frac{7}{\sqrt{36} } }$ ) = P(Z < -1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.95637 = 0.0436

(2) <em>Now, here sample of NBA players is 26 so n = 26.</em>

Probability that the mean vertical leap for the 26 players will be between 27.5 and 28.5 inches is given by = P(27.5 inches < $\bar X$ < 28.5 inches) = P( $\bar X$ < 28.5 inches) - P( $\bar X$ $\leq$ 27.5 inches)

P( $\bar X$ < 28.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{28.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z < 0.36) = 0.64058 {using z table}

P( $\bar X$ $\leq$ 27.5) = P( $\frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{27.5-28}{\frac{7}{\sqrt{26} } }$ ) = P(Z $\leq$ -0.36) = 1 - P(Z < 0.36)

= 1 - 0.64058 = 0.35942

Therefore, P(27.5 inches < $\bar X$ < 28.5 inches) = 0.64058 - 0.35942 = 0.2812

6 0

3 years ago

Find the positive square root of 2 9/49<br>

yawa3891 [41]

1.47 hope this helps

3 0

2 years ago

If the sides of a triangle are in the ratio 3:4:5, prove that it is<br>right-angled triangle

lyudmila [28]

Answer:

hope this helps

Step-by-step explanation:

Let a , b , c are three sides of a triangle

a : b : c = 3 : 4 : 5

a = 3x ,

b = 4x ,

c = 5x

a² = 9x²

b² = 16x²,

c² = 25x².

c² = a² + b²

by the pythagorean theorem,

a , b , c forms a right angled Triangle.

6 0

3 years ago

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