PEMDAS
parenthasees
exponents
multipilcarion
bla bla bla
that is important to know the differnece between
2x^2 and (2x)^2
2x^2=2*x*x
(2x)^2=2*2*x*x
so
(-3b)^4=-12b^4
pemdase so look at both sides
left side
negative to an even power means result is positive
right side
-12 times b^4
the -12 is not influcnced because that is multiply and exponents come first so it will remain negative
(+)=(-)
false
you could also evaluate it
(-3b)^4=-3b*-3b*-3b*-3b=81b^4
-12b^4=-12b^4
81b^4=-12b^4
divide b^4
81=-12
false
no
X=6 is the answer for the problem
Answer:
=3(x+8)(x+1)
Step-by-step explanation:
3(x^2+9x+8)
3(x^2+8x+1x+8)
3[(x^2+8x)+(1x+8)]
3[x(x+8)+1(x+8)]
=3(x+8)(x+1)
Answer:
(-5,5)
Step-by-step explanation: add the equations in order to solve first variable. put the value in the other equations to solve the remaining variables- math way
its the 3rd one to be correct