Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
The distance between 1 - 10 1/4
____________________
1 - 10 1/4 = -9 1/4
_________________________
Answer
-9 1/4
9 1/4 (in absolute value)
Its 1/5 likely because my teacher helped me with this problem you welcome:)
3÷8+1÷8-(9÷8+5÷8)
=3÷8+1÷8-(14÷8)
=3÷8+1÷8-14÷8
=(3+1-14)÷8
=-10÷8
=-5÷4
=-1.25
