You need to find the unit rate. if you have 64/8, 8 divided by 8 = 1. 64 divided by 8 is 8
<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
Answer:
1r
Step-by-step explanation:
(5r-4)(2r-6r+4)
1(5r-4)+1(2r-6r+4)
5r-4+2r-6r+4
5r+2r-6=1r
1r-4+4
-4+4=0
1r
Answer:
1920 in³
Step-by-step explanation:
The volume of the water can be gotten by calculation the volume of the aquarium it fills/occupies.
Since the water fills to exactly three inches below the top of the aquarium, hence the height of the water in the aquarium is given as:
height of water = 13 in - 3 in = 10 in
Therefore the volume of the water in the tank is given by the formula:
Volume of water = height of water * breadth of tank * length of tank
Volume of water = 10 in * 8 in * 24 in = 1920 in³