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eimsori [14]
3 years ago
13

Tavon makes another box with height h inches from a piece of cardboard that meadures 12 inches by 12 inches

Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

Area = 4h^2-56h +144

Step-by-step explanation:

Given

See attachment for complete question

Required: The base area.

From the question, we have the initial dimensions to be:

Length = 12

Width = 12

h inch were removed from each corner to form the new base. So, the dimension of the new base is:

Base\ Length = Length - h - h

Base\ Length = Length - 2h

Base\ Width = Width - h-h

Base\ Width = Width - 2h

The area of the base is calculated by multiplying the base dimensions

Area = Base\ Length * Base\ Width

Area = [Length - 2h] * [Width - 2h]

Area = [12 - 2h] * [12 - 2h]

Expand

Area = 12[12 - 2h] -2h [12 - 2h]

Area = 144 - 28h -28h + 4h^2

Area = 144 -56h + 4h^2

Rewrite as:

Area = 4h^2-56h +144

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Which of the following statements is true if m∠E = m∠Y and m∠F = m∠X?
mars1129 [50]

Answer:

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX

Step-by-step explanation:

see the attached figure to better understand the problem  

we know that  

If m∠E = m∠Y and m∠F = m∠X  

then  

Triangles EFG and YXZ are similar by AA Similarity Theorem  

Remember that  

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent  

In this problem  

The corresponding sides are  

FE and XY  

EG and YZ  

GF and ZX  

so therefore  

segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX Firstly , let us learn about trigonometry in mathematics.  

Suppose the ΔABC is a right triangle and ∠A is 90°.  

sin ∠A = opposite / hypotenuse

cos ∠A = adjacent / hypotenuse

tan ∠A = opposite / adjacent

Let us now tackle the problem!  

A similar triangle has the same angle, in other words the triangle has the same shape but different sizes.  

From the figure in the attachment , we can conclude that:  

m∠E = m∠Y  

m∠F= m∠X  

m∠G = m∠Z  

∴ ΔEFG ~ ΔYXZ  ( ΔEFG is similar to ΔYXZ )    

Because of the similarity , then:  

FE : XY = EG : YZ = GF : ZX  

Conclusion:

ΔFG is similar to ΔYXZ.  

Segment FE over segment XY equals segment EG over segment YZ equals segment GF over segment ZX , i.e:    

Keywords: Sine , Cosine , Tangent , Opposite , Adjacent , Hypotenuse , Triangle , Fraction , Lowest , Function , Angle

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