Answer:
Her adjusted body weight is 78.26kg = 78.3kg, rounded to the nearest tenth.
Step-by-step explanation:
To find the Adjusted Body Weight(AjBW), first we have to consider the Ideal Body Weight(IBW).
We have the following formulas:
, in which i is the number of inches that the woman has above 5 feet.
, in which 
is her Actual Body Weight
So, in this problem:
Each pound has 0.45kg. So her weight is 
kg.
The woman is 8 inches above 5 feet, so 
.
kg
Her ideal body weight is 63.9kg. Her adjusted body weight is:
kg
Her adjusted body weight is 78.26kg = 78.3kg.
Step-by-step explanation:
10±10±30±30=80
8round = 80×8=640
<h2>don't forget me to follow</h2>
2000=1800(1.04)^t,,log(1.11)/log(1.04)=t use the calculator,,,hope it helps :-)
Answer:
Step-by-step explanation:
1. Solution for 3(6a)a=3 equation:
Simplifying
3(6a) * a = 3
Remove parenthesis around (6a)
3 * 6a * a = 3
Multiply 3 * 6
18a * a = 3
Multiply a * a
18a2 = 3
Solving
18a2 = 3
Solving for variable 'a'.
Move all terms containing a to the left, all other terms to the right.
Divide each side by '18'.
a2 = 0.1666666667
Simplifying
a2 = 0.1666666667
Take the square root of each side:
a = {-0.408248291, 0.408248291}
2.Solution for 5d(4)d=-2 equation:
Simplifying
5d(4) * d = -2
Reorder the terms for easier multiplication:
5 * 4d * d = -2
Multiply 5 * 4
20d * d = -2
Multiply d * d
20d2 = -2
Solving
20d2 = -2
Solving for variable 'd'.
Move all terms containing d to the left, all other terms to the right.
Divide each side by '20'.
d2 = -0.1
Simplifying
d2 = -0.1
Reorder the terms:
0.1 + d2 = -0.1 + 0.1
Combine like terms: -0.1 + 0.1 = 0.0
0.1 + d2 = 0.0
The X-intercepts: (1,0),(-7,0)
Axis of symmetry: x= - 3
The vertex: (-3, -8)
The Y-intercept: (0, -7/2)
Concave up or down: concave up
Sketch: a poorly drawn picture on the bottom.
I hope that helps.
