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Inessa [10]
2 years ago
14

If x = 3(y+w)– 1, what is the value of w in terms of x and y?

Mathematics
1 answer:
bixtya [17]2 years ago
7 0
The answer for that is the second one
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Write the slope-intercept form of the equation of each line.​
yanalaym [24]

Answer:

y=mx+b

y=x+3

Step-by-step explanation:

m: 1 (rise over run by 1)

b: 3

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2 years ago
Explain how to change a negative exponent to a positive one
VikaD [51]

Answer:

Step-by-step explanation:

Negative exponents in the numerator get moved to the denominator and become positive exponents. Negative exponents in the denominator get moved to the numerator and become positive exponents.

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2 years ago
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Jessica's shoebox is 20 centimeters long and 10 centimeters wide. How many more millimeters is the length of the shoebox than th
Solnce55 [7]
The length is 20-10=10 cm longer than the width. That is: 10 cm * 10 mm/cm = 100 mm
7 0
2 years ago
Four more than the quotient of a number and 3 is 9
barxatty [35]

The algebraic expression of "Four more than the quotient of a number and 3 is 9" is \frac{x}{3}+4=9

The value of x=15

Step-by-step explanation:

We need to express "Four more than the quotient of a number and 3 is 9" as algebraic expression.

Let the number = x

Solving:

quotient of a number and 3: \frac{x}{3}

Four more than the quotient of a number and 3: \frac{x}{3}+4

Four more than the quotient of a number and 3 is 9: \frac{x}{3}+4=9

Now, finding value of x:

\frac{x}{3}+4=9\\Adding\,\,-4\,\,on\,\,both\,\,sides:\\\frac{x}{3}+4-4=9-4\\\frac{x}{3}=5\\Multiply\,\,both\,\,sides\,\,by\,\,3:\\x=5*3\\x=15

So, value of x = 15

Keywords: Algebraic expression

Learn more about algebraic expression at:

  • brainly.com/question/1600376
  • brainly.com/question/1617787
  • brainly.com/question/9720317

#learnwithBrainly

4 0
2 years ago
A car braked with a constant deceleration of 16ft/s2, producing skid marks measuring 200 feet before coming to a stop. How fast
Llana [10]

Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.

Step-by-step explanation:

The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,

a = - 16ft/s^2

While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.

This means that it travelled a distance,

s = 200 feet

We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.

Since the car came to a stop, its final velocity, v = 0

Applying Newton's equation of motion,

v^2 = u^2 + 2as

0 = u^2 - 2 × 16 × 200

u^2 = 6400

u = √6400

u = 80 ft/s

7 0
3 years ago
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