<em>How do air masses flow?</em>
<em>from regions of high pressure to low pressure</em>
.
In general, cold air masses tend to flow toward the equator and warm air masses tend to flow toward the poles.
The equation is:
Ca(OH)₂(s) + 2 HCl(aq) → CaCl₂(aq) + 2 H₂<span>O(l)
</span>
n=mass in g/M.M
15 g Ca(OH)₂ is n=15 g/ 74.1 g/mol=0.2024 mol of Ca(OH)₂
no. of mol of HCl:
n=0.5 mol/L*0.075L=0.0375 mol
This could react with 0.0375/2= 0.01875 mol of Ca(OH)₂ We have a lot more than that.
Therefore, HCl is the limiting reagent and determines how much CaCl₂ forms.
Based on the balanced reaction, 2 moles of HCl gives 1 mole of CaCl₂
no. of mol of CaCl₂= 0.0375/2= 0.01875 mol
mass in g=n*MM= 0.01875*111= 2.08 g
Answer:
Explanation:
To solve this problem, we have to remember the ideal gas theory. We going to use the Gay Lussac Law.
The equation is:
PiTo = PoTi
Where:
<em>Pi =initial pressure</em>
<em>Po = final pressure</em>
<em>Ti = initial temperature</em>
<em>To = final temperature</em>
Let's use this equation and replace the values:
<em>Pi = 107 kPa</em>
<em>Ti = 22°C</em>
<em>To = 45 °C </em>
<em>Po = ? </em>
<em />
You can use the units as the problem gave you.
Using the Gay Lussac law:
107 kPa x 45 °C = Po x 22°C
Po = (4,815 kPa°C / 22°C) = 218.86 kPa
Po = 218 kPa
Answer:
it will not be soluble in water Becoz it can only be
separated by passing it through silver nitrate solution
Explanation:
i hope you understand
Basedbon dilution formula, the volume of 12 M HCl required is 45 mL.
<h3>What is dilution?</h3>
Dilution is the process of preparing a less concentrated solution from a more concentrated solution.
The dilution formula is as follows:
From the given data:
C2 = 2.4 M
V2 = 2.25 mL
C2 = 12 M
V1 = ?
V1 = C2V2/C1
V1 = 2.4 × 225/12
V2 = 45 mL
Therefore, the volume of 12 M HCl required is 45 mL.
Learn more about dilution at: brainly.com/question/24881505
