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Leona [35]
3 years ago
13

What do Lewis dot structures show?​

Chemistry
1 answer:
inessss [21]3 years ago
8 0

Answer:

They display the number of valence electrons surrounding an element or compound.

Explanation:

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After conducting SDS-PAGE, you will conduct a staining/destaining procedure, which allows for visual identification of the prote
expeople1 [14]

Answer:

Add 700mL of water.

Explanation:

The technique of separation known as the Sodium Dodecyl Sulfate Poly-Acrylamide Gel Electrophoresis in which its acronym is SDS- PAGE is a very important aspect of Chemistry and Biochemistry as the technique make use of molar mass when it work in seperating proteins.

From the question we have the following parameters or information:

Case 1=> 50% of methanol which is the same as saying 50mL in 100mL of water.

Case 2=> 0.1% Comasse Blue dye (dry powder) which is the same as saying 0.1g in 100mL of water.

Case 3=> 10% acetic acid is the same as saying 10mL in 100mL of water.

Adding the three together, we have ;

50mL in 100mL of water + 0.1g in 100mL of water + 10mL in 100mL of water.

The volume of water in the three = 100 mL + 100mL + 100mL = 300mL.

Therefore, there is need to add 700mL of water to make 1L.

That's 700mL of water + 300mL = 1000mL = 1L

8 0
3 years ago
HELP
GarryVolchara [31]
It’s B Have Ah Good Day
7 0
3 years ago
Read 2 more answers
Im chemistry we are solving chemical reactions and on the assignments our teacher put the questions as riddels and I can not get
lara31 [8.8K]
Are they trying to be funny about it?
6 0
4 years ago
Design a synthesis of 2-ethoxy-2-methylpropane from 2-methylpropene.
Usimov [2.4K]

In the presence of Hg (OAc)2, the alkenes reacts with alcohol to give allkoxy-mercurated product followed by reduction with NaBH4 to give ether. This reaction is known as alkoxymercuration-demercuration reaction.

4 0
4 years ago
2.1 g of a hydrocarbon fuel is burned in a calorimeter that contains 280 grams of water initially at 25.00◦C. After the combusti
olga2289 [7]

Answer:

\large \boxed{\text{933 J}}

Explanation:

There are three heat transfers involved.

heat from combustion of propane + heat gained by water + heat gained by calorimeter = 0

  q₁     +     q₂      +       q₃      = 0

m₁ΔH + m₂C₂ΔT + C_calΔT = 0

Data:

 m₁ =      2.1   g

 m₂ = 280     g

   Ti = 25.00 °C

   T_f = 26.55 °C

Ccal = 92.3 J·°C⁻¹

Calculations:

Let's calculate the heats separately.

1. q₁

q₁ = 2.1 g × ΔH = 2.1ΔH g

2. q₂

ΔT = T_f - Ti = 26.55 °C - 25.00 °C = 1.55 °C

q₂ = 280 g × 4.184 J·°C⁻¹ × 1.55 °C = 1816 J

3. q₃

q₃ = 92.3 J·°C⁻¹ × 1.55 °C = 143.1 J

4. ΔH

\begin{array}{rcl}\text{2.1$\Delta$H g +1816 J +143.1 J} & = & 0\\\text{2.1$\Delta$H g +1959 J} & = & 0\\\text{2.1$\Delta$H g}& = & \text{-1959 J}\\\Delta H & = & \dfrac{\text{-1959 J}}{\text{2.1 g}}\\\\& = & \textbf{-933 J/g}\\\end{array}\\\text{The combustion releases $\large \boxed{\textbf{933 J}}$ per gram of fuel burned.}

7 0
3 years ago
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