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zhannawk [14.2K]
3 years ago
15

Can someone give a decent explanation to why the answer is N-2?

Chemistry
1 answer:
lapo4ka [179]3 years ago
6 0
The answer to what?????
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a rectangular piece of aluminum foil measures 13.72 cm x 8.63 cm and has a mass of 3.1 g. Find how thick it is
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The two dimensions of aluminum foil are given 13.72 cm and 8.63 cm respectively with mass  3.1 g.

The density of aluminum is 2.7 g/cm^{3}. It is defined as mass per unit volume thus, volume of aluminum can be calculated as follows:

V=\frac{m}{d}

Putting the values.

V=\frac{3.1 g}{2.7 g/cm^{3}}=1.148 cm^{3}

The volume of cuboid is l\times b\times h, the length and breadth are given, height can be calculated as follows;

h=\frac{V}{l\times b}

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h=\frac{1.148 cm^{3}}{(13.72 cm)(8.63 cm)}=0.009695 cm

Or, approximately 9.7\times 10^{-3}cm

Therefore, thickness of aluminum foil is 9.7\times 10^{-3}cm

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