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Marizza181 [45]
2 years ago
8

How many moles of Al2O3 will be formed when 27 grams of Al reacts completely with O2?

Chemistry
1 answer:
ruslelena [56]2 years ago
3 0

Explanation:

mole = mass in g/ molecular weight

molecular weight of Al2O3 =2(13) + 3(16) =74g/mol

reacting mass = 27 g

mole = 27/74 = 0.36mol

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Can someone pls help me with this question
artcher [175]

Answer:

The answer to your question is 24.325

Explanation:

Data

Magnesium-24  Abundance = 78.70%

Magnesium-25  Abundance = 10.13%

Magnesium-26  Abundance = 11.17%

Process

1.- Convert the abundance to decimals

Magnesium-24  Abundance = 78.70/100 = 0.787

Magnesium-25  Abundance = 10.13/100 = 0.1013

Magnesium-26  Abundance = 11.17/100 = 0.1117

2.- Write an equation

Average atomic mass = (Atomic mass-1 x Abundance 1) + (Atomic mass 2 x

                                       Abundance-2) + (Atomic mass 3 x Abundance 3)

3.- Substitution

Average atomic mass = (24 x 0.787) + (25 x 0.1013) + (26 x 0.1117)

4.- Simplification

Average atomic mass = 18.888 + 2.533 + 2.904

5.- Result

Average atomic mass = 24.325

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What makes the factor that makes the sky appear blue?
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