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Nata [24]
3 years ago
14

Fill in the missing number to name a fraction equivalent 8/3

Mathematics
1 answer:
anastassius [24]3 years ago
7 0

Answer:

72/27

Step-by-step explanation:

Because all you have to do is multiply by any number to the numerator and denominator same number I used 9 for some reason but since you multiplied them both by the same number the new fraction will be equivalent

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8(3(2x+3y)) what does it equal?
rjkz [21]

Hello from MrBillDoesMath!

Answer:

48x + 72y

Discussion:

8(3(2x+3y))    =                               => as 8*3 = 24

24 (2x + 3y)    =

24*2x + 24*3y =

48x + 72y

Thank you,

MrB

7 0
3 years ago
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Joanna, Mary, Betty, and Leah ran a race. Joanna's time was 13.03 seconds, Mary's was 13.284 seconds,
alina1380 [7]

Answer:

1st-joanna

2nd-Mary

3rd-Betty

4th-leah

Step-by-step explanation:

joanna won the race

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3 years ago
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How do you solve for a and b?
natali 33 [55]
You need to isolate b on one side of the equation then divide both side by h finally move b on the other side of the equation by subtracting it from both sides of the equation and then you have what b equals to
5 0
3 years ago
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In the morning, a farm worker packed 4 pints of grapes every 5 minutes. In the afternoon, she packed 3 pints of grapes every 6 m
balandron [24]

Answer:

25

Step-by-step explanation:

4 0
3 years ago
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Find the value of b.
Nesterboy [21]

Answer: 230^{\circ

Step-by-step explanation:

For convenience, I labeled some points as shown in the attached picture.

Also, I assume \overline{AB} and \overline{BC} are tangents to the circle.

  1. \overline{BO} \cong \overline{BO} (reflexive property)
  2. \overline{AB} \cong \overline{BC} (tangents drawn from a common external point are congruent)
  3. \angle BAO \cong \angle BCO (right angles are congruent)

Therefore, we know \triangle ABO \cong \triangle CBO by HL.

Thus, by CPCTC,

\angle AOB \cong \angle BOC \implies m\angle BOC=65^{\circ}\\\\\implies m\angle AOC=130^{\circ}

This means the measure of minor arc AC is 130^{\circ}, and thus b=360^{\circ}-130^{\circ}=\boxed{230^{\circ}}

7 0
1 year ago
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