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Nata [24]
3 years ago
14

Fill in the missing number to name a fraction equivalent 8/3

Mathematics
1 answer:
anastassius [24]3 years ago
7 0

Answer:

72/27

Step-by-step explanation:

Because all you have to do is multiply by any number to the numerator and denominator same number I used 9 for some reason but since you multiplied them both by the same number the new fraction will be equivalent

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What is the first quartile of 10, 12, 19, 20, 24, 26, 30, 31, 34, 36
nasty-shy [4]
19 would be the first quartile.
7 0
2 years ago
A postcard in the shape of a parallelogram has an area of 12in^2. What are two possible lengths of bases and heights for the pos
Tpy6a [65]

A postcard is in the shape of a parallelogram. A parallelogram  is a quadrilateral with two pair of parallel sides, opposite sides and opposite angles are equal.

Since, the postcard has an area of 12 square inches.

Since, area of parallelogram = base \times height

As area of parallelogram is 12, it means that the product of base and height is 12 square inches.

So, the possible dimensions of postcard are 3 inches and 4 inches and 2 inches and 6 inches.

So, base = 3 inches , height = 4 inches or base = 4 inches , height = 3 inches.

So, base = 2 inches, height = 6 inches or base = 6 inches , height = 2 inches.

8 0
3 years ago
3 1/2 divided by 2 3/5
melomori [17]

Step-by-step explanation:

31/2×5/23 (use reciprocal)

31×5=155

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155/46

3 and 17/46

8 0
2 years ago
Read 2 more answers
The town librarian bought a combination of new-release movies on DVD for $20 and classic movies on DVD for $8. Let x represent t
Galina-37 [17]

Answer:

x = 1, y = 60

Step-by-step explanation:

Value of new-releases (x) = $20 each

Value of classic (y) = $8 each

Total budget = $500

Equation : 20x + 8y = 500

The librarian wants to purchase maximum DVDs. She can get more DVDs of classic movies for $8 as they are less costly.

Lets assume the librarian buys at least one new-release DVD.

x=1

20x + 8y = 500

8y + 20(1) = 500

y = 60

<em>Therefore, in a budget of $500, the librarian can purchase 60 classic movies and 1 new-release.</em>

!!

8 0
3 years ago
The strength of a cable is proportional to the square of its diameter. If a 2-cm cable will support 800kg, how much will a 3-cm
xz_007 [3.2K]
Strength [is proportional to] d^2
strength1/(d1)^2 = strength2/(d2)^2
800kg/(2cm)^2 = strength2/(3cm)^2
strength2 = 800 kg * (3 cm)^2/(2 cm)^2
strength2 = 800 kg * 3^2/2^2
strength2 = 800 kg * 9/4
strength2 = 1800 kg
3 0
3 years ago
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