There are several information's already given in the question. Based on those information's the answer can be detrmined.
Smaller of the two integers = n
Larger of the two integers = n + 1
Then
(1/2) * [(n) * ( n + 1)] = 105
(1/2) * (n^2 + n) = 105
m^2 + n = 210
n^2 + n - 210 = 0
From the above deduction, it can be concluded that the correct option among all the options that are given in the question is the first option or option "A".
P=12T
Q=66T
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Toys added to each bag:
P=12T+nT
Q=66T+nT
Therefore, 66T+nT=3(12T+nT)
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66T+nT=36T+3nT
T(66+n)=T(36+3n)
66+n=36+3n
3n-n=66-36
2n=30
Therefore, n=30/2=15
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*She added 15 toys to each bag.
Answer:
The answer is below
Step-by-step explanation:
Plotting the following constraints using the online geogebra graphing tool:
x + 3y ≤ 9 (1)
5x + 2y ≤ 20 (2)
x≥1 and y≥2 (3)
From the graph plot, the solution to the constraint is A(1, 2), B(1, 2.67) and C(3, 2).
We need to minimize the objective function C = 5x + 3y. Therefore:
At point A(1, 2): C = 5(1) + 3(2) = 11
At point B(1, 2.67): C = 5(1) + 3(2.67) = 13
At point C(3, 2): C = 5(3) + 3(2) = 21
Therefore the minimum value of the objective function C = 5x + 3y is at point A(1, 2) which gives a minimum value of 11.
Answer:
16
Step-by-step explanation:
1/4 pie=4
2/4 pie= 8
3/4 pie= 12
4/4pie= 16
A is (2,-4) B (-2,5) C (0,-6) D(-4,-3) E(3,0) F(5,4)
