The hypothesis is given as
H0: μd< 0
H1: μd > 0
<h3>How to solve for the hypothesis.</h3>
The null hypothesis is given as
H0: μd< 0
<h3>The alternative hypothesis is given as </h3>
H1: μd > 0
SWe have to find the value of s
we would use this formula s = sqrt [ (Σ(di - d)^2 / (n - 1) ]
This gives us 3.454
Next we have to determine the standard error
s / √(n)
3.454/2.8284
= 1.22
Degree of freedom = 8 - 1
= 7
t = (x1 - x2) - D / S.E
= 1.025
Find t critical at 0.10
= 1.895
P-value = 0.1697
d. Given that p value is greater thatn 0.1 we fail to reject the null hypothesis.
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For this problem, 0.25 in = 50 m. So
11 in = (11 in) • (50/0.25 m/in) = 2200 m
Alternatively, if 0.25 in = 50 m, that means 1 in = 200 m. So 11 in = 11 (200 m) = 2200 m.
So, we'll say Mia gets $4.50 a day, since a standard weekend is two days, therefore adding up to $9 a weekend. So if Mia were to do her chores for 4 weekends, she'd have a total of $36 but not $40. So if she were to work an extra weekend, so 5 weekends, she'd have a total of $45. So you can say 5 weekends in order to earn more than $40.
First is yes
Second is no
Third is no
Fourth is no
It would be 1%. If you divide 2/200, you get 0.01. When multiplied by 100, you get 1.