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Kruka [31]
3 years ago
11

Is 0=(x+4)^2-7 rational or irrational

Mathematics
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

Irrational.

Step-by-step explanation:

0=(x+4)^2-7

(x + 4)^2 = 7

Taking square roots:

x + 4  =  ±√7

x = -4 ±√7

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Va rog e urgent am nevoie de raspuns
Lady_Fox [76]

Answer: 4

<u>Explanation:</u>

f(x) = 2x - 1

f(√2) = 2√2 - 1

f(1) = 2(1) - 1

     =  2 - 1

     =     1

f(√3)  = 2√3 - 1

*******************************************************

\frac{f(\sqrt{2})-f(1)}{\sqrt{2}-1} +\frac{f(\sqrt{3})-f(\sqrt{2})}{\sqrt{3}-\sqrt{2}}

= \frac{(2\sqrt{2}-1)-1}{\sqrt{2}-1} +\frac{(2\sqrt{3}-1)-(2\sqrt{2}-1)}{\sqrt{3}-\sqrt{2}}

= \frac{2\sqrt{2}-2}{\sqrt{2}-1} +\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}

= \frac{2\sqrt{2}-2}{\sqrt{2}-1}(\frac{\sqrt{2}+1}{\sqrt{2}+1})+\frac{2\sqrt{3}-2\sqrt{2}}{\sqrt{3}-\sqrt{2}}(\frac{\sqrt{3}+\sqrt{2}}{\sqrt{3}+\sqrt{2}})

= \frac{4+2\sqrt{2}-2\sqrt{2}-2}{2 - 1} + \frac{6 +2\sqrt{6}-2\sqrt{6}-4}{3-2}

= \frac{2}{1} +\frac{2}{1}

= 4

3 0
3 years ago
Compute Δy and dy for the given values of x and dx = Δx. (Round your answers to three decimal places.) Compute Δy and dy for the
Darina [25.2K]
Base on the data you have given and with my calculation, i think the best value for Delta X and Dy is delta x = 2 and the DY = 1/2.I hope you are satisfied with my answer and feel free to ask for more if you have more clarifications and further questions
3 0
3 years ago
Read 2 more answers
VW = WX = YW = ZX = VX = view image attached thank youuu!
jeka57 [31]

Answer:

assuming this is a rectangle:

VW=31

WX=19

YW=36.36

ZX=18.18

VX=36.36

Step-by-step explanation:

VW=VX

VW=31

WX=VX

WX=19

YW^2=19^2+31^2

YW^2=361+961

YW^2=1322

YW=36.36

ZX=1/2VX

ZX=18.18

VX=YW

VX=36.36

3 0
3 years ago
What is sixty three hundred in number form
SOVA2 [1]

Answer:

Step-by-step explanation:

600,399

4 0
3 years ago
Read 2 more answers
A force of 12 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i
sattari [20]

Answer:

Work done in stretching the spring = 7.56 lb-ft.

Step-by-step explanation:

Normal length of the spring = 8 in or \frac{8}{12} ft

= \frac{2}{3} ft

If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in

= \frac{11}{12} ft

Force applied to stretch the spring = 12 lb

By Hook's law,

F = kx [where k is the spring constant and x = length by which the spring is stretched]

12 = k(\frac{2}{3})

k = 18

Work done (W) to stretch the spring by \frac{11}{12} ft will be

W = \int\limits^\frac{11}{12} _0 {kx} \, dx

    = \int\limits^\frac{11}{12} _0 {(18x)} \, dx

    = 18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0

    = 9(\frac{11}{12})²

    = 7.56 lb-ft

6 0
3 years ago
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