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Sholpan [36]
2 years ago
12

On a coordinate plane, triangle A has points (0, 0), (negative 2, 3), (2, 3). Triangle A prime has points (0, 0), (negative 3, n

egative 5), (3, negative 5).
The pre–image, A, was dilated about the origin. It was then transformed in another way to get A'.

What was the transformation after the dilation?
rotation 90° counterclockwise
translation down 9 units
reflection over the x-axis
reflection over the y-axis
Mathematics
2 answers:
shutvik [7]2 years ago
8 0

Answer:

c

Step-by-step explanation:

Kipish [7]2 years ago
5 0

Answer:

C-reflection over the x-axis

Step-by-step explanation:

edge 2021

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I NEED HELP AHHH-HHHHHHHHH HELP ME ASAP
zvonat [6]

Answer:

1/5, 1/3, 4/6

Step-by-step explanation:

First, find all the common denominators for these numbers. In this case, it's 30.

1/5 = 10/30

4/6 = 20/30

1/5 = 6/30

Now, you can see which ones are greatest and least.

1. 1/5 (least)

2. 1/3 (middle)

3. 4/6  (greatest)

4 0
3 years ago
What is the slope-intercept equation<br> for the following line?<br> y = [?]x + []
Alexus [3.1K]

Answer:

y=-4x-3

I Hope It Helps!

7 0
3 years ago
X:2 (105-275:11):4=28
balandron [24]
X:2+(105-275:11):4=28
X:2+(105-25):4=28
X:2+80:4=28
X:2+20=28
X:2=28-20
X:2=8
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4 0
3 years ago
Write the expression (X+6)(x-4) as a polynomial in standard form.
zmey [24]

Answer:

Just

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7 0
2 years ago
7.<br>(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)​
serg [7]

Answer:

-\frac{x^2y^2}{2}

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}

Multiply the numerators :

\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}

Multiply the denominators :

\frac{-18x^6y^4z^3}{36x^4y^2z^3}

Apply the negative rule :

-\frac{18x^6y^4z^3}{36x^4y^2z^3}

Cancel the common factor which is 18 :

-\frac{x^6y^4z^3}{2x^4y^2z^3}

Apply the addition exponent rule :

\frac{y^4z^3x^{6-4} }{2y^2z^3}

Subtract :

\frac{x^2y^4z^3 }{2y^2z^3}

Apply the rule for y :

\frac{x^2y^{4-2} z^3 }{2z^3}

Subtract :

\frac{x^2y^2z^3 }{2z^3}

Cancel the common factor of z^3 :

-\frac{x^2y^2}{2}

5 0
3 years ago
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