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Sholpan [36]
3 years ago
12

On a coordinate plane, triangle A has points (0, 0), (negative 2, 3), (2, 3). Triangle A prime has points (0, 0), (negative 3, n

egative 5), (3, negative 5).
The pre–image, A, was dilated about the origin. It was then transformed in another way to get A'.

What was the transformation after the dilation?
rotation 90° counterclockwise
translation down 9 units
reflection over the x-axis
reflection over the y-axis
Mathematics
2 answers:
shutvik [7]3 years ago
8 0

Answer:

c

Step-by-step explanation:

Kipish [7]3 years ago
5 0

Answer:

C-reflection over the x-axis

Step-by-step explanation:

edge 2021

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Write a situation in which positive and negative numbers are used to describe values that have opposite meaning. What does a 0 r
MrRa [10]
This could be a situation in which items are both bought and sold. In calculating the inventory, positive numbers represent items bought, negative numbers represent items sold and 0 would be no items in the inventory.

Another type of situation would be the displacement of an object from the original position. Where 0 would represent the original/starting position, positive values would represent distance moved forward, negative values represent distance moved backwards. 
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Which estimate is closest to the answer of this number sentence?
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The answer is 11 :)))))
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6. If n (E) = 40, n (A) = 22, n (ANB) = 8 and n ((AUB)') = 6, determine n(B)​
Dimas [21]

Answer:

4

Step-by-step explanation:

First n(AUB)=n(E) - n((AUB)')

So n(AUB) = 40 - 6 = 34

Now all u hv to do is use the formulae,

n(AUB) = n(A) + n(B) - n(ANB)

So when u substitute above values,

34=22 + n(B) - 8

So,

n(B) = 4

4 0
3 years ago
A man buys a certain number of Litchies at 20 per rupee and equal number at 30 per rupee. He
ANTONII [103]

Full question :

A man buys a certain number of oranges at 20 for Rs. 60 and an equal number at 30 for Rs. 60. He mixes them and sells them at 25 for Rs. 60. What is the gain or loss percent?

Answer:

4% loss(percentage loss on cost price)

Step-by-step explanation:

we will be employing algebra in solving this problem :

20 oranges at 60 Rs=60Rs/20 per orange=3Rs per orange

Say x oranges bought at 3Rs per orange=3Rsx

Equal number of oranges at 30 oranges for 60 Rs=60Rs/30 per orange=2Rs per orange

Say x oranges bought at 3Rs per orange=2Rsx

Total Cost Price = 3Rsx + 2Rsx = 5Rsx

He then sells all oranges at 25 for 60 Rs

Therefore price per orange=60/25=12/5Rs

since he sold x+x oranges(from the above calculations)

Total selling price=total oranges *12/5Rs=2x oranges*12/5Rs=24x/5Rs

Profit or loss=24x/5-5x=-x/5

therefore we have a loss =-x/5

Percentage of loss(on cost price)

=x/5÷5x∗100=

=1/25∗100=4%

5 0
3 years ago
the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const
laiz [17]
In general, the volume

V=\pi r^2h

has total derivative

\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)

If the cylinder's height is kept constant, then \dfrac{\mathrm dh}{\mathrm dt}=0 and we have

\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}

which is to say, \dfrac{\mathrm dV}{\mathrm dt} and \dfrac{\mathrm dr}{\mathrm dt} are directly proportional by a factor equivalent to the lateral surface area of the cylinder (2\pi r h).

Meanwhile, if the cylinder's radius is kept fixed, then

\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}

since \dfrac{\mathrm dr}{\mathrm dt}=0. In other words, \dfrac{\mathrm dV}{\mathrm dt} and \dfrac{\mathrm dh}{\mathrm dt} are directly proportional by a factor of the surface area of the cylinder's circular face (\pi r^2).

Finally, the general case (r and h not constant), you can see from the total derivative that \dfrac{\mathrm dV}{\mathrm dt} is affected by both \dfrac{\mathrm dh}{\mathrm dt} and \dfrac{\mathrm dr}{\mathrm dt} in combination.
8 0
3 years ago
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