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Goryan [66]
3 years ago
12

What is the equation of the line that passes through the point (-4, 2) and has a slope of 1/4?​

Mathematics
1 answer:
natulia [17]3 years ago
5 0

Answer:

y = 1/4x + 3

Step-by-step explanation:

m = 1/4, (-4,2)

y -2 = 1/4(x - - 4)

y - 2 = 1/4 (x + 4)

y - 2 = 1/4x + 1

y = 1/4x + 1 + 2

y = 1/4x + 3

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What is the slope of the line that is perpendicular to the line that goes through the two points (-8, 3) and (4, 27)?
Mademuasel [1]

Answer:

-1/2 or -0.5

negative half

Step-by-step explanation:

slope of regular line= (y1-y2) / (x1-x2)

(27-3) / (4 - -8)

24 / (4+8)

24 / 12 = 2

the slope of a perpendicular line is the negative reciprocal

the negative reciprocal of positive 2/1 (2 as a fraction) is:

negative half: -1/2 or -0.5

8 0
2 years ago
Find the measure of each exterior angle of a regular 56-gon.
Karo-lina-s [1.5K]
The answer is 6 degree.

Step by step process

The formula for calculating the measure of each exterior angle of a polygon is (360/n).

The number of sides of 56-gon(n) = 56.


So, each exterior angle
= (360/56)
= 6.43 or
6(approximately)
4 0
3 years ago
Make a comparison true. Drag and drop tenth value to fill in the blank. Select all that apply. 24. _ > 24. 34
spayn [35]

Answer:

Step-by-step explanation:

These items may be used by Louisiana educators for educational purposes. Grade 7 Answer Key. ITEM 14. Use the table to answer the question.

3 0
2 years ago
Solve the proportion using cross products. Round to the nearest hundredth if necessary. $18.45/m gal = $3.60/7.5gal
sveta [45]
\dfrac{\$18.45}{n \text { gallon}}  =  \dfrac{\$3.60}{7.5 \text { gallon}}

Cross multiply
n \times \  3.60 = 7.5 \times \  18.45

Combine like terms
3.60n = 138.375

Find n
n = 138.375\div 360

Answer
n = 0.38 \text { (nearest hundredth)}
3 0
2 years ago
Read 2 more answers
PLEASE HELP!!! WILL GRANT BRAINLIEST IF CORRECT, NEED NOW
Vinil7 [7]

Answer:

B

Step-by-step explanation:

For each equation, set x to 0.  A is correct because if x=o, then y will equal 38.910.

5 0
3 years ago
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