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3 years ago

Use < >, or = to compare the following decimals.

Mathematics

1 answer:

Contact [7]3 years ago

4 0

Answer:

0.32, 0.45, 0.76.

Step-by-step explanation:

so first you would use your < >,= signs and compare all of them until you have eliminated ALL but one (so 0.91<0.98 this is because 0.98 is close to 1 whole than 0.91) and you would continue this explanation for so on

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You are driving on a freeway with a posted speed of 65 mph. Nearly all of the cars are traveling between 35 and 40 mph. What wou

marissa [1.9K]

30 mph would be a safe speed for you to drive.

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2 years ago

select yes or no to indicate if a rectangle with the given dimensions whould have a perimeter of 50 inches

umka21 [38]

1a) no it would be 54

1b) yes

1c) yes

1d) no it would be 40

1e) yes

hope this helped

8 0

3 years ago

During an experiment, Aika measured the time it took for a ball to roll down a ramp set at an angle. She measured that it took 1

schepotkina [342]

Answer:

11.725%

Step-by-step explanation:

Given that :

True value = 0.904 seconds

Measured time = 1.010 seconds

Experimental error :

(|measured value - True value | / true value) * 100%

(|1.010 - 0.904| ÷ 0.904) * 100%

= 0.106 / 0.904 * 100%

= 0.1172566 * 100%

= 11.725%

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3 years ago

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A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0

3 years ago

A 16-ft ladder is placed 4 ft. from the base of a

Alex73 [517]

Answer:

You have a right triangle.

a^2+b^2=c^2

4^2+b^2=256

16+b^2=256

b^2=256-16

b^2=240

b=sqrt240

b=15.49 ft. ans. for the height of the ladder up the wall.

Step-by-step explanation:

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3 years ago

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