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ExtremeBDS [4]
2 years ago
5

Edhesive code practice 4.8 Question 3

Computers and Technology
2 answers:
True [87]2 years ago
8 0
For in rang 200,301,2
vovangra [49]2 years ago
3 0

Answer:

for i in range(200,301,2):

  print(i)

Explanation:

just copy and paste 100 percent

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Something the user knows (ID and password); something the user has (such as a smart card, which is a credit card device storing
Vlad1618 [11]

Answer:

Secure Authentication involves a combination of the following three information

Explanation:

Generally, it is important that users have access to secure sources of information or data. These data will be used by the users to get access to their platform such as account details. The user should also be the only person that has access to his or her vital information. This should not be disclosed to any other person.

8 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Font changes can only be applied on a word-by-word basis.<br><br><br> A.True<br><br><br> B.False
Sergio039 [100]
B. False, it doesnt only have to be applied word by word


3 0
3 years ago
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What's the best way to use a lectern during your speech?
valentina_108 [34]

<span>Make eye contact look at everyone ur speaking to not just one person speak loud and clearly make sure your understandable</span>
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3 years ago
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How do you know when a spreadsheet object is active in a Word document?      A. The Ribbon is minimized. B. The Excel Formula ba
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Y<span>ou will know when a spreadsheet object is active in a Word document </span>t<span>he Word icon in the taskbar is selected. The ribbon of Word will provide you with the Microsoft Excel features to be used for editing. These include charts, conditional formatting, and formulas.</span>
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