Answer:
Explanation:
try
clc
clear
close all
x=linspace(0,2*pi,7);
z=cos(pi.*x./3)
% the output on mine is to 4 decimals so it looks a bit different than what the output on your example is , but, I think if you change the format to decimal 2 it will look the same :)
Answer: Logical Point Blocking
Explanation:
Answer:
a) Generate a new public and private key
Explanation:
You encrypt a message using the recipient's public key and the recipient decrypts the message using his own private key. Only the public key can be known by an external agent. The private key is for the individual and is not expected to be shared. In the event that the recipient cannot decrypt the message, it is unsafe to send one's private key to him. He does not even need one's private key to decrypt the message, he needs his own private key.
The best thing to do is to generate another means of security by generating new public and private key so that the sender encrypts the message with the new public key and the receiver decrypts it using his new private key.
Option B is wrong because, if the encryption is removed, the aim, which is to secure the message from intruders is not achieved.
Observing, Looking, Collecting, there are a few words for "gathering information with your eyes".
